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4 years ago

5

The picture below shows a soil texture triangle.

1 answer:

lys-0071 [83]4 years ago

4 0

Referring to the given diagram, we will find that the percentage of sand in silt is given on the base of the triangle.
The amount of sand is almost 50% of silt. Representing this on the percentage line, we will find that the percentage of sand is somewhere between the 40% and the 60%.

Based on the above, the best choice would be:
c. 40 percent to 60 percent

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A 10.0-kg box starts at rest and slides 3.5 m down a ramp inclined at an angle of 10° with the horizontal. If there is no fricti

Alenkinab [10]

Answer:

$v_f = 3.45 m/s$

Explanation:

As we know that box was initially at rest

so here work done by all forces on the box = change in its kinetic energy

so we will have

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now we have

m = 10 kg

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so we will have

$10(9.81)sin10 \times 3.5 = \frac{1}{2}(10)(v_f^2 - 0)$

$2(9.81) sin10 \times 3.5 = v_f^2$

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3 years ago

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iragen [17]

Nuclear, thermal and I think cemical idk

8 0

3 years ago

1. A ball is launched horizontally at 40 m/s while 6.0 m above a level field . How far will the ball move horizontally before st

Tresset [83]

Answer:

44 m

Explanation:

Given that,

Horizontal velocity of the ball, u = 40 m/s

It is 6 m above the level field.

We need to find the distance covered by the ball when move horizontally before striking the ground. Let it is d.

Firstly, we will find time taken for the ball to hit the ground. Using second equation of motion as follows :

$s=ut+\dfrac{1}{2}at^2$

Put u = 0 and a = g

$s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 6}{9.8}} \\\\t=1.1\ s$

No finding the horizontal distance as follows :

d = ut

d = 40 m/s × 1.1 s

d = 44 m

So, the ball will move 44 m horizontally before striking the ground.

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3 years ago

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never [62]

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3 years ago

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Arlecino [84]

Answer: C
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Read 2 more answers