Answer:
Barometric pressure is 942.3 cm of column of water.
Explanation:
We can measure barometric pressure by measuring the height h of a column of fluid (this column of fluid exerts the same pressure as the column of air of which we are measuring pressure) using the following formula:

Where ρ is the density of the fluid used and g the acceleration of gravity.
Knowing that both the column of mercury (to match units, we know that 698 mmHg are the same as 69.8 cmHg) and the column of water are representing the same pressure, we can match expressions and find h for the column of water:

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Answer:
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Answer:
Coefficient in front of the
in the balanced equation - 1
Explanation:
The unbalanced Chemical equation is shown below as:-
On the left hand side,
There are 1 boron atom and 3 fluorine atoms and 1 sodium and hydrogen atoms.
On the right hand side,
There are 2 boron atoms and 6 hydrogen atoms and 1 sodium and fluorine atoms.
Thus,
leftside,
must be multiplied by 2 to balance boron and right side,
must be multiplied by 6 to balance fluorine. Left side,
must be multiplied by 6 to balance sodium and hydrogen atoms.
Thus, the balanced reaction is:-
<u>Coefficient in front of the
in the balanced equation - 1</u>
Answer:
V ≈ 2.9 L H₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<u>Chemistry - Reactions</u>
- Aqueous Solutions and states of matter
- Reaction Prediction
<u>Chemistry - Gas Laws</u>
Combined Gas Law: PV = nRT
- P is pressure
- V is volume in liters
- n is amount of moles of substance
- R is a constant - 62.4 (L · mmHg)/(mol · K)
- T is temperature in Kelvins
Temperature Conversion: K = °C + 273.15
Explanation:
<u>Step 1: Define</u>
Unbalanced RxN: Zn (s) + HCl (aq) → ZnCl₂ (aq) + H₂ (g)
Balanced RxN: Zn (s) + 2HCl (aq) → ZnCl₂ (aq) + H₂ (g)
Given: 7.68 g Zn, 20.00 °C, 740 mmHg
<u>Step 2: Identify Conversions</u>
Kelvin Conversion
Molar Mass of Zn - 65.39 g/mol
<u>Step 3: Convert</u>
Stoichiometry:
= 0.117449 mol H₂
Temp Conversion: 20.00 + 273.15 = 293.15 K
<u>Step 4: Find V</u>
- Substitute: (740 mmHg)V = (0.117449 mol)(62.4 (L · mmHg)/(mol · K))(293.15 K)
- Multiply: (740 mmHg)V = 2148.45 L · mmHg
- Isolate<em> V</em>: V = 2.9033 L H₂
<u>Step 5: Check</u>
<em>We are given 2 sig figs as our lowest. Follow sig fig rules and round.</em>
2.9033 L H₂ ≈ 2.9 L H₂