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stealth61 [152]
3 years ago
8

Please help to Calculate the lower and upper bound for 3.2 + 4.6​

Physics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

<h3>i think it is 7.10 </h3>

Explanation:

I dont  have an explenation    

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Which characteristic gives the most information about what kind of element an atom is ?
Butoxors [25]

Answer:

The atomic number

Explanation:

7 0
3 years ago
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B. On a separate sheet of paper, describe the different ways of generating electric power. ​
Afina-wow [57]

Answer:

These all different sources of energy add to the store of electrical power that is then sent out to different locations via high powered lines. It is the energy from the sun that is harnessed using a range of technologies such as solar heating, solar architecture, photovoltaics, and artificial photosynthesis.

Hope it helps PLS MARK ME AS BRAINLIST I BEG YOU thanks :)

4 0
2 years ago
Between which two points of a concave mirror should an object be placed to obtain a magnificati of -3​
kobusy [5.1K]

Answer:

When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.

When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.

Explanation:

8 0
3 years ago
A 400g sample of water absorbs 500j of energy. how did the water temperature change if the specific heat of water is 4.18j/g©. S
Mashutka [201]

In general, the quantity of heat energy, Q, required to raise a mass m kg of a substance with a specific heat capacity of <span>c </span>J/(kg °C), from temperature t1 °C to t2 °C is given by:

<span>Q </span>= <span>mc(t</span><span>2 </span><span>– t</span>1<span>) joules</span>

<span>So:</span>

(t2-t1) =Q / mc

<span>As we know:
Q = 500 J </span>

<span>m = 0.4 kg</span>

<span>c = 4180 J/Kg </span>°c

<span>We can take t1 to be 0</span>°c

t2 - 0 = 500 / ( 0.4 * 4180 )

t2 - 0 = 0.30°c

6 0
3 years ago
If no heat is lost to the surroundings, how much heat must be added to raise the temperature from 20.0 ∘C to 85.0 ∘C ?
andrey2020 [161]

Answer:

Explanation:

C_{water} = 4190 J/kg.K

C_{Al} = 910 J/Kg. K

m_{Al} = 1.50 kg

m_{water} = 1.80 kg

Q_{added} = Q_{Al} + Q_{water}

=m_{Al} C_{Al}ΔT + m_{water} C_{water}ΔT

= (1.50)(910)(85.0-20)+(1.80)(4190)(85.0-20)

= 578,955 J

= 579 kJ

3 0
3 years ago
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