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stealth61 [152]
3 years ago
8

Please help to Calculate the lower and upper bound for 3.2 + 4.6​

Physics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

<h3>i think it is 7.10 </h3>

Explanation:

I dont  have an explenation    

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Light travels slowest in high density media, faster in lower density media, and fastest in low density media.
lutik1710 [3]

Answer: C REFRACTION

Explanation: I took the test and got it right lol <3

8 0
2 years ago
Determine the mass of a boat that is propelled forward by a force of 1250N at an acceleration of 3 m/s2.
Pavlova-9 [17]

Answer:

416.6 KG

Explanation:

Due to the mass being missing from the equation you divide the force by the acceleration

6 0
3 years ago
What is the relationship between the frequency and the pitch of a sound?
jarptica [38.1K]
The pitch of a sound come from the frequency of the soundwave, soundwaves that have bigger frequencies sound with a high pitch and soundwaves with less frequencie have low pitch.
6 0
3 years ago
A man hits a 50 grams golf ball such that it leaves the tee at an angle of 40o with the horizontal and strikes the ground at the
lukranit [14]

Answer:

Explanation:

Range of projectile R = 20 m

formula of range

R = u² sin2θ / g

u is initial velocity , θ is angle of projectile

putting the values

20 = u² sin2x 40 / 9.8

u² = 199

u = 14.10 m /s

At the initial point

vertical component of u

= u sin40 = 14.1 x sin 40

= 9.06 m/s

Horizontal component

= u cos 30

At the final point where the ball strikes the ground after falling , its speed remains the same as that in the beginning .

Horizontal component of velocity

u cos 30

Vertical component

= - u sin 30

= - 9.06 m /s

So its horizontal component remains unchanged .

change in vertical component = 9.06 - ( - 9.06 )

= 18.12 m /s

change in momentum

mass x change in velocity

= .050 x 18.12

= .906 N.s

Impulse = change in momentum

= .906 N.s .

3 0
3 years ago
For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency
Angelina_Jolie [31]

Answer:

2.7 J

Explanation:

The energy of one photon is given by

E=hf

where

h is the Planck constant

f is the frequency

For the photons in this problem,

f=6.8\cdot 10^9 Hz

So the energy of one photon is

E_1=(6.63\cdot 10^{-34})(6.8\cdot 10^9 )=4.5\cdot 10^{-24} J

The number of photons contained in 1.0 mol is

N_A = 6.022\cdot 10^{23} mol^{-1} (Avogadro number)

So the total energy of N_A photons contained in 1.0 mol is

E=N_A E_1 =(6.022\cdot 10^{23})(4.5\cdot 10^{-24})=2.7 J

3 0
3 years ago
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