3 years ago

Please help to Calculate the lower and upper bound for 3.2 + 4.6

Physics

1 answer:

PSYCHO15rus [73]3 years ago

8 0

Answer:

<h3>i think it is 7.10 </h3>

Explanation:

I dont have an explenation

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what was the acceleration of the cart with Low fan speed cm/s squared? what was the acceleration of the cart with medium fan spe

ArbitrLikvidat [17]

Explanation:

The attached figure shows data for the cart speed, distance and time.

For low fan speed,

Distance, d = 500 cm

Time, t = 7.4 s

Average velocity,

$v=\dfrac{d}{t}\\\\v=\dfrac{500}{7.4}\\\\v=67.56\ cm/s$

Acceleration,

$a=\dfrac{v}{t}\\\\a=\dfrac{67.56}{7.4}\\\\a=9.12\ cm/s^2$

For medium fan speed,

Distance, d = 500 cm

Time, t = 6.4 s

Average velocity,

$v=\dfrac{d}{t}\\\\v=\dfrac{500}{6.4}\\\\v=78.12\ cm/s$

Acceleration,

$a=\dfrac{v}{t}\\\\a=\dfrac{78.12}{6.4}\\\\a=12.2\ cm/s^2$

For high fan speed,

Distance, d = 500 cm

Time, t = 5.6 s

Average velocity,

$v=\dfrac{d}{t}\\\\v=\dfrac{500}{5.6}\\\\v=89.28\ cm/s$

Acceleration,

$a=\dfrac{v}{t}\\\\a=\dfrac{89.28}{5.6}\\\\a=15.94\ cm/s^2$

Hence, this is the required solution.

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3 years ago

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What layer of the atmosphere is hot but does not have enough gas molecules to transfer heat to you (i.e., you would not feel the

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Answer:

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3 years ago

You are doing x-ray diffraction on a crystal that has a cubic structure, using 0.340-nm x rays. Part A If the lattice spacing is

Mrac [35]

Answer:

∅ = 0.26°

Explanation:

Bragg's law states that:

n×λ = 2×d×sin(∅)

<em>where:</em>

<em>d is the lattice spacing.</em>
<em>λ is the wavelength of the rays.</em>
<em>n is the order of the diffracted rays, n = 1.</em>

then:

sin(∅) = λ/2×d

∅ = sin^-1(λ/2×d)

∅ = 0.26°

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Where is a divergent boundary most likely to be found?

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Answer:

mid-ocean oceanic ridges

Explanation:

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You walk forward at 1.5 m/s for 8s. Your friend decides to walk faster and starts out at 2.0 m/s for the first 4 s. Then she slo

Troyanec [42]

The first thing you should know is that the distance is equal to the speed per time.
Therefore if You walk forward at 1.5 m / s for 8s
d = 1.5t [0,8] s
Your friend decides to walk faster and starts at 2.0 m / s for the first 4 s.
d = 2t [0,4] s
Then she slows down and walks forward at 1.0 m / s for the next 4s
d = t + 4 [4,8] s
Who walked farther?
They both walked the same distance
12 meters

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3 years ago

Please help to Calculate the lower and upper bound for 3.2 + 4.6​

Please help to Calculate the lower and upper bound for 3.2 + 4.6