Let m = mass of earth
<span>let r = radius of earth </span>
<span>let a = acceleration due to gravity on earth </span>
<span>G = constant (it doesn't change) </span>
<span>If you plug in the mass and radius of the new planet, you get </span>
<span>a = G (.5m)/(2r)^2 </span>
<span>a = 1/8 (Gm/r^2) </span>
<span>so the acceleration on the new planet is 1/8 what it is here.</span>
Answer
given,
height of object = 2.7 cm
distance left of lens (u₁)= 20 cm
focal length of lens(f₁)= 10 cm
the distance of image



v₁ = 20 cm
magnification of first lens


m₁ = -1
distance of object from the second lens
u₂ = 52-20 = 32 cm
f₂ = 48 cm
now,



v₁ = 624 cm
magnification of first lens


m₁ = -12
total magnification
m = m₁ m₂
m = (-1)(-12)
m = 12
height of image


h' = -32.4 cm
a) distance between image and second lens is equal to 624 cm
b) height of image is equal to 32.4 cm
Answer:
The bowling ball
Explanation:
The PE (gravitational potential energy) of an object is given by:

where
m is the mass of the object
g is the gravitational acceleration
h is the height of the object above the ground
In this case, we are comparing the PE of a bowling ball and of a ping pong ball. The two balls are located at same height (h=5 m) and the gravitational acceleration is the same (g=9.8 m/s^2), so their PE depends only on their mass: since the bowling ball has a greater mass than the ping pong ball, the bowling ball will have a greater PE.
Answer:
Explanation:
length of the wire = L
Potential difference = Vo
Current = I
new length of the wire, L' = L/2
As we know that the resistance of the wire is directly proportional to the length of the wire.
As the length is halved so that the resistance is also halved.
Resistance = Voltage / Current
V = I R
So, Voltage is constant and the resistance is halved so that the current is doubled.