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kupik [55]
2 years ago
8

I just don’t know what to do

Chemistry
1 answer:
ValentinkaMS [17]2 years ago
3 0

Answer:

I dont know if this is correct.. but maybe in the tool row, put graduated cylinder because you use graduated cylinders to measure water and for units put milliliters or liters?? Sorry if this isnt correct i wouldnt know what else to put !

Explanation:

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klemol [59]

Answer:

what are you asking?

Explanation:

7 0
2 years ago
1. How many moles are in 230. Grams of SO2?
Georgia [21]

3.59 mol

1.836 x 10 ²⁵ molecules

<h3>Further explanation</h3>

Given

230 g SO2

30.5 moles LiNO3

Required

moles and molecules

Solution

mol = mass : molar mass

1 mol = 6.02 x 10²³ particles(molecules, atoms, ions)

1. 230 g x 1 mol/64,066 g  =3.59 mol

2. 30.5 moles x 6.02 x 10 ²³ molecules / 1 mol = 1.836 x 10 ²⁵ molecules

5 0
2 years ago
I have two solutions : solution A has 6 moles of solute in 2 L of solvent; solution B has 6 moles of solute in 1 L of solvent .
12345 [234]

Answer:

Many people have a qualitative idea of what is meant by concentration. Anyone who has made instant coffee or lemonade knows that too much powder gives a strongly flavored, highly concentrated drink, whereas too little results in a dilute solution that may be hard to distinguish from water. In chemistry, the concentration of a solution is the quantity of a solute that is contained in a particular quantity of solvent or solution. Knowing the concentration of solutes is important in controlling the stoichiometry of reactants for solution reactions. Chemists use many different methods to define concentrations, some of which are described in this section.

Molarity

The most common unit of concentration is molarity, which is also the most useful for calculations involving the stoichiometry of reactions in solution. The molarity (M) is defined as the number of moles of solute present in exactly 1 L of solution. It is, equivalently, the number of millimoles of solute present in exactly 1 mL of solution:

molarity=molesofsolutelitersofsolution=mmolesofsolutemillilitersofsolution(4.5.1)

(4.5.1)molarity=molesofsolutelitersofsolution=mmolesofsolutemillilitersofsolution

The units of molarity are therefore moles per liter of solution (mol/L), abbreviated as MM . An aqueous solution that contains 1 mol (342 g) of sucrose in enough water to give a final volume of 1.00 L has a sucrose concentration of 1.00 mol/L or 1.00 M. In chemical notation, square brackets around the name or formula of the solute represent the molar concentration of a solute. Therefore,

[sucrose]=1.00M(4.5.2)

(4.5.2)[sucrose]=1.00M

is read as “the concentration of sucrose is 1.00 molar.” The relationships between volume, molarity, and moles may be expressed as either

VLMmol/L=L(molL)=moles(4.5.3)

(4.5.3)VLMmol/L=L(molL)=moles

or

VmLMmmol/mL=mL(mmolmL)=mmoles(4.5.4)

(4.5.4)VmLMmmol/mL=mL(mmolmL)=mmoles

Figure 4.5.14.5.1 illustrates the use of Equations 4.5.34.5.3 and 4.5.44.5.4 .

alt

Figure 4.5.14.5.1 : Preparation of a Solution of Known Concentration Using a Solid Solute

Example 4.5.14.5.1 : Calculating Moles from Concentration of NaOH

Calculate the number of moles of sodium hydroxide (NaOH) in 2.50 L of 0.100 M NaOH.

Given: identity of solute and volume and molarity of solution

Asked for: amount of solute in moles

Strategy:

Use either Equation 4.5.34.5.3 or Equation 4.5.44.5.4 , depending on the units given in the problem.

Solution:

Because we are given the volume of the solution in liters and are asked for the number of moles of substance, Equation 4.5.34.5.3 is more useful:

molesNaOH=VLMmol/L=(2.50L)(0.100molL)=0.250molNaOHmolesNaOH=VLMmol/L=(2.50L)(0.100molL)=0.250molNaOH

Exercise 4.5.14.5.1 : Calculating Moles from Concentration of Alanine

Calculate the number of millimoles of alanine, a biologically important molecule, in 27.2 mL of 1.53 M alanine.

6 0
2 years ago
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