Answer:
1) C₃H₄N
Explanation:
The empirical formula of a compound is the formula that gives the positive integer ratio of the atoms of the elements in the compound in the simplest form
The mass of carbon in the compound = 90 grams
The molar mass of carbon = 12.011 g/mol
The number of moles of carbon = 90 g/(12.011 g/mol) ≈ 7.4931313 moles
The mass of hydrogen in the compound = 11 grams
The molar mass of hydrogen = 1.00794 g/mol
The number of moles of carbon = 11 g/(1.00794 g/mol) ≈ 10.913348 moles
The mass of nitrogen in the compound = 35 grams
The molar mass of nitrogen = 14.0067 g/mol
The number of moles of carbon = 35 g/(14.0067 g/mol) ≈ 2.49880414 moles
Dividing by the smallest mole ratio gives;
The proportion of carbon, C = 7.4931313/2.49880414 = 2.9987 ≈ 3
The proportion of nitrogen, N = 10.913348 /2.49880414 = 4.367 ≈ 4
The proportion of nitrogen, N = 2.49880414 /2.49880414 = 1
Therefore, the empirical formula of the compound is C₃H₄N.
