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devlian [24]
3 years ago
10

Ralphie runs north 0.5 km, then turns east and runs 2.0 km, turns south and runs 1.5 km, turns west and runs another 1km. What i

s is distance he ran?
2√ km square root of 2 km
-2 km
2 km
5 km
Physics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

I think its 2km

Explanation:

bc if u put it out on a graph, it would essentially take about 4 jumps to get to your ending point, and assuming each jumb was 0.5 km. But if u dont trust me look at another answer bc I dont know if thats right or not.

You might be interested in
8) Calculate the kinetic energy of a truck that has a mass of 6100 kg and is moving at 55 m/s.
Inessa [10]

Answer:

<h2>9,226,250 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

v is the velocity

m is the mass

From the question we have

k =  \frac{1}{2}  \times 6100 \times  {55}^{2}  \\  = 3050 \times 3025 \\  = 9226250

We have the final answer as

<h3>9,226,250 J</h3>

Hope this helps you

7 0
3 years ago
I attach a 4.1 kg block to a spring that obeys Hooke's law and supply 3.8 J of energy to stretch the spring. I release the block
borishaifa [10]

Answer:

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

T = 2\pi \sqrt{\frac{m}{k} }

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

T = 2\pi \sqrt{\frac{m}{k} } \\\\k = \frac{m*4\pi ^2}{T^2} \\\\k = \frac{4.1*4*(3.142^2)}{(0.13^2)} \\\\k = 9580.088 \ N/m\\\\

Now, determine the amplitude of oscillation, A;

E = \frac{1}{2} kA^2

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

E = \frac{1}{2} kA^2\\\\2E = kA^2\\\\A^2 = \frac{2E}{k} \\\\A = \sqrt{\frac{2E}{k} } \\\\A =  \sqrt{\frac{2*3.8}{9580.088} }\\\\A = 0.0282 \ m\\\\A = 2.82 \ cm

Therefore, the amplitude of the oscillation is 2.82 cm

8 0
3 years ago
What is a travelling wave and a standing wave? What are the differences between both of them?
solniwko [45]
What is a travelling wave and a standing wave? What are the differences between both of them?

Answer: First of all we have to understand that a traveling wave is an organized disturbance traveling with a well defined wave speed. On the other hand standing waves are the combination of period waves with their reflected waves creating double sided waves. The differences between them is that standing waves have nodes and antinodes while a traveling wave does not.

I hope it helps, Regards.
7 0
3 years ago
Read 2 more answers
Determine the total impedance of an LRC circuit connected to a 10.0- kHz, 725-V (rms) source if L = 36.00 mL, R = 10.00 kΩ, and
SOVA2 [1]

Answer:

10042.6 ohm

Explanation:

f = 10 kHz = 10000 Hz, L = 36 mH = 0.036 H, R = 10 kilo Ohm = 10000 ohm

C = 5 nF = 5 x 10^-9 F

XL = 2 x π x f x L

XL = 2 x 3.14 x 10000 x 0.036 = 2260.8 ohm

Xc = 1 / ( 2 x π x f x C) = 1 / ( 2 x 3.14 x 10000 x 5 x 10^-9)

Xc = 3184.7 ohm

Total impedance is Z.

Z^2 = R^2  + (XL - Xc)^2

Z^2 = 10000^2 + ( 2260.8 - 3184.7 )^2

Z = 10042.6 ohm

4 0
3 years ago
What is the time lapse between seeing a lightning strike and hearing the thunder if the lightning flash is 47 km away? The speed
Natali5045456 [20]

Answer:

141.14098 secs

Explanation:

Time taken to see the lightning flash can be gotten from:

Velocity = distance/time

Time = distance/velocity

Time = (47 * 1000)/(3 * 10^8)

Time = 0.0001567 secs

Time taken to hear the thunder can be gotten from:

Velocity = distance/time

Time = distance/velocity

Time = (47 * 1000)/(333)

Time = 141.14114 secs

The time lapse between the lightning flash and the thunder will be:

141.14114 - 0. 0001567

= 141.14098 secs

6 0
3 years ago
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