The answer might be C ? hope it's right
Answer:
2.5 cm
Explanation:
Using the relation :
Refractive index = Real Depth / Apparent depth
Refractive index = 1.6
Real depth = 4cm
Virtual depth = apparent depth = x
1.6 = 4cm / x
1.6x = 4
x = 4 / 1.6
x = 2.5
Hence, virtual depth = 2.5cm
At the end of the laps, the runner's displacement is zero.
The answer is A 1/4f because it is doubled to 2q and you need to flip it