3 years ago

In the formation of an ionic compound, a metal atom is most likely to _____ valence electrons

Physics

2 answers:

nalin [4]3 years ago

4 0

In the formation of an ionic compound, a metal atom is most likely to lose valence atoms.

AleksAgata [21]3 years ago

4 0

<span>_____ valence electrons

The correct answer is lose
</span>

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The first collision because a greater amount of momentum must be taken and used in order to push the cart back, giving it a greater mass and impulse

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3 years ago

A train increase its speed steadily from 10m/s to 20m/s in 1minutes A what is the average speed during this time in m/s B how fa

Ipatiy [6.2K]

If it increased its speed steadily at a constant rate, then the average speed for the minute was

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3 years ago

a force 2.4E2 N exists between a positive charge of 8E-5 C and a positive charge of 3E-5 C. What distance separates the charges?

Verdich [7]

The distance between the two charges is $0.3 m$

Explanation:

The electrostatic force between two charged objects is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the charges of the two objects

r is the separation between the two charges

In this problem, we are given the following:

$q_1 = 8\cdot 10^{-5} C$

$q_2 = 3\cdot 10^{-5} C$

$F=2.4\cdot 10^2 N$

Therefore, we can rearrange the equation to solve for r, the distance between the two charges:

$r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(8.99\cdot 10^9)(8\cdot 10^{-5})(3\cdot 10^{-5})}{2.4\cdot 10^2}}=0.3 m$

Learn more about electrostatic force:

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3 years ago

HURRY The compressed spring of a dart gun has potential energy of 50 J. If the spring constant is 200 N/m, what is the displacem

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Spring potential energy:
E = 0.5 * k * x²

k spring constant
x spring compression

x = √(2 * E / k) = 0.7

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3 years ago

Read 2 more answers

A sled with a mass of 20 kg slides along frictionless ice at 4.5 m/s. It then crosses a rough patch of snow that exerts a fricti

uysha [10]

Answer:The sled slides 16.875m before rest.

Explanation:

$a=\frac{F}{m} =\frac{12N}{20kg}$

a=0.6 m/s²

$Vf=0=Vi-a.t$

$t=\frac{Vi}{a} =t=\frac{4.5m/s}{0.6 m/s2} =t=7.5seg$

$d= Vi.t - \frac{a.t^{2}}{2}$

$d= 4.5 * 7.5 - \frac{0.6*7.5^{2} }{2} \\\\d=16.875m$

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3 years ago