Answer: d. Remove one-half of the initial CaCO3.
Explanation: Le Chatelier's principle states that changes on the temperature, pressure, concentration and volume of a system will affect the reaction in an observable way. So in the reaction above:
A decrease in temperature will shift the equilibrium to the left because the reaction is exothermic, which means heat is released during the reaction. In other words, when you decrease temperature of a system, the equilibrium is towards the exothermic reaction;
A change in volume or pressure, will result in a production of more or less moles of gas. A increase in volume or in the partial pressure of CO2, the side which produces more moles of gas will be favored. In the equilibrium above, the shift will be to the left.
A change in concentration will tip the equilibrium towards the change: in this system, removing the product will shift the equilibrium towards the production of more CaCO3 to return to the equilibrium.
So, the correct answer is D. Remove one-half of the initial CaCO3.
This is one of the ideal gas laws. Presumably the pressure remains the same so it is not part of the givens.
Formula
V / T = V1 / T1
Givens
- V = 56.05 mL
- T = 315.1 degrees Kelvin
- V1 = x
- T1 = 380.5 degrees Kelvin
Solution
56.05/315.1 = x/380.5 Simplify the left.
0.1779 = x / 380.5 Multiply both sides by 380.5
0.1779 * 380.5 = 380.5x/380.5
67.68 mL = x This is your answer
Answer:
See explanation.
Explanation:
Hello!
In this case, we can proceed as follows:
1. Here, the undergoing chemical reaction is:
Thus, the moles and mass of water turn out:
2. Here, the undergoing chemical reaction is:
So the required moles of HCl and the yielded of water are:
3. Here, the undergoing chemical reaction is:
Now, we apply each mole ratio obtain:
A.
B.
Best regards!
Answer is: 1. HClO₃; (chloric acid).
Balance chemical reaction (dissociation):
ClO₃⁻(aq) + H₂O(l) ⇄ HClO₃(aq) + OH⁻(aq).
According
to Bronsted-Lowry theory acid are donor of protons and bases
are acceptors of protons (the hydrogen cation or H⁺).
The chlorate anion (ClO₃⁻) is Bronsted base and it
can accept proton and become conjugate acid HClO₃..
