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ahrayia [7]
3 years ago
14

Solve for d: 7d = –35

Mathematics
1 answer:
34kurt3 years ago
5 0
7d = - 35
d = - 5

anything 2 ask please pm me
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g Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = 7yi + xzj + (
Sati [7]

By Stokes' theorem,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

where S is any oriented surface with boundary C. We have

\vec F(x,y,z)=7y\,\vec\imath+xz\,\vec\jmath+(x+y)\,\vec k

\implies\nabla\times\vec F(x,y,z)=(1-x)\,\vec\imath-\vec\jmath+(z-7)\,\vec k

Take S to be the ellipse that lies in the plane z=y+9 with boundary on the cylinder x^2+y^2=1. Parameterize S by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(u\sin v+9)\,\vec k

with 0\le u\le1 and 0\le v\le2\pi. Take the normal vector to S to be

\vec s_u\times\vec s_v=-u\,\vec\jmath+u\,\vec k

Then we have

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{2\pi}\int_0^1\big((1-u\cos v)\,\vec\imath-\vec\jmath+(u\sin v+2)\,\vec k\big)\cdot\big(-u\,\vec\jmath+u\,\vec k\big)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^1(3u+u^2\sin v)\,\mathrm du\,\mathrm dv=\boxed{3\pi}

5 0
3 years ago
-3× + 33= -12 ×= whats the answerr​
Lena [83]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Identify any zeros of y=x^2+4x+5.
Jet001 [13]

A there are no real zeros

using the discriminant b² - 4ac  to determine the nature of the zeros

for y = x² + 4x + 5 ( with a = 1, b = 4 and c = 5 )

• If b² - 4ac > 0 there are 2 real and distinct zeros

• If b² - 4ac = 0 there is a real and equal zero

• If b² - 4ac < 0 there are no real zeros

b² - 4ac = 16 - 20 = - 4

Since discriminant < 0 there are no real zeros



3 0
2 years ago
Write an equation for each problem. Then solve.
Nana76 [90]

Answer:

<em>The price is the same at both stores for 2 prints.</em>

Step-by-step explanation:

<u>Equations</u>

Let's set the variable

x = number of photo prints

Company Photo Plus charges $2 for each print and $6 for a processing fee, thus the total charges are:

PP = 6 + 2x

Company Picture Time charges $3 for each print and $4 for a processing fee, thus it charges a total of:

PT = 4 + 3x

It's required to find the number of prints that make both stores charge the same. Equating both functions:

6 + 2x = 4 + 3x

Subtracting 2x and 4:

x = 2

The price is the same at both stores for 2 prints.

4 0
3 years ago
Shera is building a cabinet she is making wooden braces for the corners of the cabinet. What is the surface area
MA_775_DIABLO [31]
The correct answer for the question that is being presented above is this one: "28 in^2." 

We have to get the individual area of each surface.
A1 = 1*3*2 = 6
A2 = 1*3*2 = 6
A3 = 1*2*2 = 4
A4 = 2*3*2 = 12
Area = A1 + A2 + A3 + A4 
Area = 6 + 6 + 4 + 12
Area = 28 in^2
7 0
3 years ago
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