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3 years ago

Which of the following ocean-floor features would contain the newest rocks?

2 answers:

7 0

The further away from the mid-ocean ridge, the older the rocks are on the ocean floor. Therefore, the ocean floor feature that would contain the newest rocks would be the mid-ocean ridge.

victus00 [196]3 years ago

4 0

Answer: Mid-ocean ridge

A mid-ocean ridge is an underwater mountain landmass generated after the plate tectonics. It forms when the ocean floor is uplifted by the magma generated by the rise of convection current during the divergent plate tectonics. The rocks generated by this process is due to the solidification of the lava after underwater volcanic eruption. Therefore, mid-ocean ridge likely to form new rocks in the oceanic bed.

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Glycerin is poured into an open U-shaped tube until the height in both sides is 20cm. Ethyl alcohol is then poured into one arm

Liula [17]

Answer:

7.5 cm

Explanation:

In the figure we can see a sketch of the problem. We know that at the bottom of the U-shaped tube the pressure is equal in both branches. Defining $\rho_A:$ Ethyl alcohol density and $\rho_G:$ Glycerin density , we can write:

$\rho_A\times g \times h_1 + \rho_G \times g \times h_2 = \rho_G \times g \times h_3$

Simplifying:

$\rho_A\times h_1 = \rho_G \times (h_3 - h_2) (1)$

On the other hand:

$h_1 + h_2 = \Delta h + h_3$

Rearranging:

$h_1 - \Delta h = h_3 - h_2 (2)$

Replacing (2) in (1):

$\rho_A\times h_1 = \rho_G \times (h_1 - \Delta h)$

Rearranging:

$\frac{h_1 \times (\rho_A - \rho_G)}{- \rho_G} = \Delta h$

Data:

$h_1 = 20 cm; \rho_A = 0.789 \frac{g}{cm^3}; \rho_G = 1.26 \frac{g}{cm^3}$

$\frac{20 cm \times (0.789 - 1.26) \frac{g}{cm^3}}{- 1.26\frac{g}{cm^3}} = \Delta h$

$7.5 cm = \Delta h$

7 0

3 years ago

Looking straight downward into a rain puddle whose surface is covered with a thin film of gasoline, you notice a swirling patter

Ivanshal [37]

Answer:

Explanation:

Point beneath you forms a beautiful iridescent green

refractive index of Gasoline $n=1.38$

Wavelength of Green light is $\lambda =540\ nm$

Here light first traverse from air(n=1) to gasoline , it reflects from front surface of gasoline(n=1.38) so it suffers a phase change. After this light reflect from rear surface of gasoline and there is a decrease in refractive index(n=1.38 to n=1.33), so there is no phase change occurs .

For constructive interference

$2t=(m+\frac{1}{2})\cdot \frac{\lambda }{n}$