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Rudik [331]
3 years ago
9

Which of the following ocean-floor features would contain the newest rocks?

Physics
2 answers:
Amiraneli [1.4K]3 years ago
7 0
The further away from the mid-ocean ridge, the older the rocks are on the ocean floor. Therefore, the ocean floor feature that would contain the newest rocks would be the mid-ocean ridge.
victus00 [196]3 years ago
4 0

Answer: Mid-ocean ridge

A mid-ocean ridge is an underwater mountain landmass generated after the plate tectonics. It forms when the ocean floor is uplifted by the magma generated by the rise of convection current during the divergent plate tectonics. The rocks generated by this process is due to the solidification of the lava after underwater volcanic eruption. Therefore, mid-ocean ridge likely to form new rocks in the oceanic bed.

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An increase in thermal energy leads to ?
Alina [70]

Answer:

When the average kinetic energy of its particles increases, the object's thermal energy increases. Therefore, the thermal energy of an object increases as its temperature increases.

3 0
3 years ago
Read 2 more answers
A meterstick is initially standing vertically on the floor. If the meterstick falls over, with what angular velocity will it hit
notsponge [240]

L = length of the meter stick = 1 m

h = height of center of mass of stick from bottom end on the floor = L/2 = 1/2 = 0.5 m

m = mass of the meter stick

I = moment of inertia of the meter stick about the bottom end

w = angular velocity as it hits the floor

moment of inertia of the meter stick about the bottom end is given as

I = m L²/3

using conservation of energy

rotational kinetic energy of meter stick as it hits the floor = potential energy when it is vertical

(0.5) I w² = m g h

(0.5) (m L²/3) w² = m g h

( L²) w² =  6g h

( 1²) w² =  6 (9.8) (0.5)

w = 5.4 rad/s

8 0
4 years ago
A football (450 g) falls vertically from rest onto the ground from a height of 5.0 m. If the force that
mario62 [17]
I don’t understand sorry
5 0
3 years ago
A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
KATRIN_1 [288]

Complete Question

Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU.  What is its orbital period?

Answer:

The value  is  T_R  = 11.8 \  days  

Explanation:

From the question we are told that

   The semi - major axis of the rocky debris  a_R = 45.0\  AU

   The semi - major axis of  Planet D is  a_D  = 60 \  AU

    The orbital  period of planet D is  T_D = 18.164 \  days

Generally from Kepler third law

          T \  \ \alpha \ \ a^{\frac{3}{2} }

Here T is the  orbital period  while a is the semi major axis

So  

        \frac{T_D}{T_R}  =  \frac{a^{\frac{3}{2} }}{a_R^{\frac{3}{2} }}

=>     T_R  = T_D *  [\frac{a_R}{a_D} ]^{\frac{3}{2} }  

=>     T_R  = 18.164  *  [\frac{ 45}{60} ]^{\frac{3}{2} }

=>      T_R  = 11.8 \  days  

   

7 0
3 years ago
4.00 kg glass coffee cup is 30.0°C at room temperature. It is then plunged into hot dishwater at a temperature of 90.0°C, as sho
statuscvo [17]

Answer:

Q = 200800 Joules.

Explanation:

Given the following data;

Mass = 4kg

Initial temperature = 30.0°C

Final temperature = 90.0°C

Specific heat capacity of glass = 837 J/kg°C

To find the quantity of heat absorbed;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 90 - 30

dt = 60°C

Substituting the values into the equation, we have;

Q = 4*837*60

Q = 200800 Joules.

Therefore, the amount of heat absorbed is 200800 Joules.

8 0
3 years ago
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