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mezya [45]
2 years ago
13

A speedboat with a mass of 511 kg (including the driver) is tethered to a fixed buoy by a strong 31.5 m cable. The boat's owner

loves high speed, but does not really want to go anywhere. So the owner revs up the boat's engine, makes a lot of noise, and runs the boat in circles around the buoy with the cable supplying all the necessary centripetal force. When the tension of the cable is steady at 13300 N, with what force is the boat's engine pushing the boat? Different physics textbooks treat drag force somewhat differently and use different formulas. For the present purpose, take the water's drag force on the boat to be (450 kg/m)×2, where denotes the boat's speed. Ignore any drag force on the cable.
Physics
1 answer:
Lady_Fox [76]2 years ago
6 0

Answer:

its is 23.09 kb

Explanation:

i did this awsner

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What are some modern uses for infrasound example, ultrasound can be used in the medical field to look inside people. Thanks!
lyudmila [28]
Infrasound sound is any sound that are below the sound a human can hear, elephants use it to communicate with other elephants.
5 0
3 years ago
An Air Force plane lands with a velocity of 125 m/s and accelerates at a maximum rate of -6.5 m/s^2.
Alisiya [41]

Answer:

a) 19.2 s

b) No

Explanation:

Given:

v₀ = 125 m/s

a = -6.5 m/s²

v = 0 m/s

a) Find: t

v = at + v₀

(0 m/s) = (-6.5 m/s²) t + (125 m/s)

t ≈ 19.2 s

b) Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (125 m/s)² + 2 (-6.5 m/s²) Δx

Δx ≈ 1200 m

An aircraft carrier that's 850 meters long won't be long enough.

8 0
4 years ago
When a ball is launched from the ground at a 45° angle to the horizontal, it falls back to the ground 50 m from the launch point
Inessa [10]

Answer:

Explanation:

Given

angle through which ball is launched=45^{\circ}

Range of ball=50 m

Range of projectile is =\frac{u^2sin2\theta }{g}

50=\frac{u^2sin90}{9.8}

u=22.136 m/s

If ball is thrown straight upward

v^2-u^2=2as

0-(22.136)^2=2(-9.8)s

s=\frac{22.136^2}{2\times 9.8}

s=25 m

(b)For Projectile time of flight is

t=\frac{2usin\theta }{g}

t=\frac{2\times 22.136\times sin45}{9.8}

t=3.19 s

7 0
3 years ago
The binding of acetylcholine to its receptor at the neuromuscular junction causes the opening of a
Rufina [12.5K]

Answer: opening of the nicotinic acetylcholine receptor channels.

Explanation:

Neuromuscular junction is a special junction formed between a motor neurone and a muscle fibre. The junction is fortified with nerves and receptors that helps in the transmission of signals from the motor neurone to the muscle fibre in order to bring about the desired voluntary movements through muscular contraction.

Nicotinic acetylcholine receptor are activated through the binding of acetylcholine at the neuromuscular junction. This action leads to influx of sodium ions to accomplish endplate potential.

7 0
3 years ago
As amplitude of a wave increases, the
agasfer [191]

i think so it is frequency

7 0
3 years ago
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