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ale4655 [162]
2 years ago
7

Environmental factors can affect an organism's appearance, behavior, and health. For example, in certain reptiles, the temperatu

re of the environment may determine the sex of the offspring. Both genetics and environmental factors determine the observable, physical characteristics of organisms, also called their _______________ in genetics.
a. phenotypes

b. organelle

c. morphology

d. genotype
Chemistry
2 answers:
andriy [413]2 years ago
5 0

Answer:

Phenotype

Explanation:

The observable physical characteristics of an organism, as determined by both genetic makeup and environmental influences.

posledela2 years ago
3 0

The question is asking about the observable physical characteristics of organisms.

We can eliminate options B and C because they don't make much sense. An <em>organelle</em> is a structure in a cell which conducts cellular functions, and the <em>morphology</em> of an organism is basically the anatomy and physiology of the organism, which isn't quite what we're looking for.

Keeping this in mind, here is some information on prefixes:

<em>geno</em> - relating to genes

<em>pheno</em> - relating to what's observable

The second one sounds a lot like what we're looking for, and just in case, <u>the definition of phenotype is the set of observable characteristics of an individual resulting from the interaction of its genotype with the environment.</u>

Therefore your answer is: A. phenotypes

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The materials in the flux covering on an electrode determine the electrical characteristics of the electrode.
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Answer:

a. true

Explanation:

It is true that, the materials in the flux covering on an electrode determine the electrical characteristics of the electrode.

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2 years ago
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Determine the pH of 0.050 M HCN solution. HCN is a weak acid with a Ka equal to 4.9 x 10-10<br> DONE
nadezda [96]

Answer:

The pH of the solution is 5.31.

Explanation:

Let "\alpha is the dissociation of weak acid - HCN.

The dissociation reaction of HCN is as follows.

                  HCN+H_{2}O\rightarrow H_{3}O^{+}+CN^{-}

Initial                  C                         0            0

Equilibrium        c(1- \alpha)              c\alpha c\alpha

Dissociation constant = Ka= c\alpha \times \frac{c\alpha}{c(1-\alpha)}

=\frac{c\alpha^{2}}{(1-\alpha)}

In this case weak acids \alpha is very small so, (1-\alpha ) is taken as 1.

Ka=C\alpha^{2}

\alpha=\sqrt\frac{ka}{c}

From the given the concentration = 0.050 M

Substitute the given value.

\alpha=\sqrt\frac{4.9\times 10^{-10}}{0.05}=9.8\times 10^{-4}

[H_{3}O^{+}]=c\alpha

[H_{3}O^{+}]=0.05\times 9.8\times 10^{-4}= 4.9\times10^{-6}

pH= -log[H_{3}O^{+}]

=-log[4.9\times10^{-6}]

=6-log 4.9= 5.31

Therefore, The pH of the solution is 5.31.

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3 years ago
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