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ale4655 [162]
3 years ago
7

Environmental factors can affect an organism's appearance, behavior, and health. For example, in certain reptiles, the temperatu

re of the environment may determine the sex of the offspring. Both genetics and environmental factors determine the observable, physical characteristics of organisms, also called their _______________ in genetics.
a. phenotypes

b. organelle

c. morphology

d. genotype
Chemistry
2 answers:
andriy [413]3 years ago
5 0

Answer:

Phenotype

Explanation:

The observable physical characteristics of an organism, as determined by both genetic makeup and environmental influences.

posledela3 years ago
3 0

The question is asking about the observable physical characteristics of organisms.

We can eliminate options B and C because they don't make much sense. An <em>organelle</em> is a structure in a cell which conducts cellular functions, and the <em>morphology</em> of an organism is basically the anatomy and physiology of the organism, which isn't quite what we're looking for.

Keeping this in mind, here is some information on prefixes:

<em>geno</em> - relating to genes

<em>pheno</em> - relating to what's observable

The second one sounds a lot like what we're looking for, and just in case, <u>the definition of phenotype is the set of observable characteristics of an individual resulting from the interaction of its genotype with the environment.</u>

Therefore your answer is: A. phenotypes

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A gas occupies a volume of 650.0 mL when the pressure is 3.50 atm. What will the new volume be if the pressure is reduced to 1.6
Gemiola [76]

The new volume will be 1379 mL.

Explanation:

As per Boyle's law, the product of initial volume and initial pressure of any gas molecule is equal to the product of final volume and final pressure of those molecules.

So here the initial volume is 650 ml and the initial pressure is 3.50 atm. As the temperature is said to be constant, then this system will be obeying Boyle's law. So, the final pressure is given as 1.65 atm. As there is a reduction in the pressure, the volume of the gas is tend to get expanded.

P_{1} V_{1} = P_{2} V_{2}

So, (650*10^{-3}*3.50)=(1.65*V_{2})

V_{2} = \frac{650*10^{-3}*3.50}{1.65} = 1379 mL

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7 0
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bixtya [17]
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prohojiy [21]

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