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Nutka1998 [239]
3 years ago
13

Use the choose reaction drop down menu to see other equations, and balance them. Check your answers and then write the balanced

equations. AI+ HCI-> AICI3+ H2
NaCI -> Na + CI2

Na2S + HCI -> NaCI + H2S​
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
6 0
3 and then you do that yea
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Which choice describes a population? A. all the gray squirrels that live in a forest B. a nonliving factor in an organism's envi
goldenfox [79]
I believe D. because all the organisms that live in a lake can be a bunch of living things that would be considered a population and not a species. I canceled out B. from the get go because, I don’t believe non living organisms can be in a population ?

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5 0
3 years ago
from the balanced equation we see that h20 is 1 to 1 mole ratio the number of moles of acid and base. What is the number of mole
forsale [732]

Answer:

0.0498 mol

Explanation:

Number of moles = concentration in mol/L × volume in L

Concentration = 1 M = 1 mol/L

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5 0
4 years ago
if the observed test value of a hypothesis test is outside of the established critical value(s), a researcher would __________.
Makovka662 [10]
The answer to this question is:

<span>If the observed test value of a hypothesis test is outside of the established critical value(s), a researcher would __________.
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6 0
3 years ago
Read 2 more answers
If 20.0 grams of Al is placed into a solution containg
meriva

Answer:

m H2(g) = 2.241 g H2(g)

Explanation:

  • 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g)

limit reagent:

∴ Mw Al = 26.982 g/mol

∴ Mw H2SO4 = 98.0785 g/mol

⇒ n Al = (20 g Al)×(mol/26.982 g) = 0.7412 mol Al

⇒ n H2SO4 = ( 115 g H2SO4 )×(mol/98.0785 g) = 1.173 mol H2SO4

⇒ n H2 = (0.7412 mol Al)×(3 mol H2/ 2 mol Al) = 1.112 mol H2

∴ Mw H2 = 2.016 g/mol

⇒ g H2 = (1.112 mol H2)×(2.016 g/mol) = 2.241 g H2

5 0
3 years ago
Ort
ivanzaharov [21]

Answer:

1 ethanol is right answer

Explanation:

CH3- CH2-OH

4 0
3 years ago
Read 2 more answers
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