Answer:
The rate of doing work is called power.
Answer:
Explanation:
An isentropic process is one that does not change the entropy of the system. A reversible of the universe, and it is reversible because of that. Real processes increase the entropy of the universe, so trying to reverse them would decrease the entropy of the universe, which is impossible, so they are irreversible.
The Carnot cycle has 4 phases:
-Isotermal expansion of gas. In this process it takes heat from a hot source. It is a reversible process, but not isentropic.
-Adiabatic expansion. This one is isentropic, the entropy of the gas remains constant and it doesn't interact with the surroundings. The gas expands not by its own, but the machine makes it expand (it pulls on the gas). The gas cools down.
-Isotermal compression. Reversible but not adiabatic. The gas exchanges heat with the cold source, reducing its volume.
-Adiabatic compression. Adiabatic and isentropic. The machine compresses the gas, causing it to heat up.
Answer:
F > W * sin(α)
Explanation:
The force needed for the box to start sliding up depends on the incline (α).
The external forces acting on the box would be the weight, the normal reaction and the lifting force that is applied to make it slide up.
These forces can be decomposed on their normal and tangential (to the slide plane) components.
The weight will be split into
Wn = W * cos(α) (in normal direction)
Wt = W * sin(α) (in tangential direction)
The normal reaction will be alligned with the normal axis, and will be equal to -Wn
N = -W* cos(α) (in normal direction)
To mke the box slide up, a force must be applied, that is opposite to the tangential component of the weight and at least a little larger
F > |-W * sin(α)| (in tangential direction)
Answer:
Incident Command Structure, ICS or ICS-like EOC Structure is familiar and aligns with the on-scene incident organization. ICS or ICS-like EOC Structure is familiar and aligns with the on-scene incident organization.
R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3
HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
HEIGHT OF IMAGE=40/3*1/-8*15/10
=-20/8
=-2.5
