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3 years ago

Identify five common business uses for electronic spreadsheets

2 answers:

4 0

For the answer to the question above
Forecasting how a business might do in the future.
Calculating tax.
Doing basic payrolls.
Calculating Revenues.
Producing charts.

--Going past 5--

Inventory tracking
Very (VERY) basic CRM for small businesses
I hope my answer helped you.

tiny-mole [99]3 years ago

3 0

Electronic spreadsheet uses vary from simple calculations to complex numerical solutions. In business, it may be used for (1) organizing statistical and financial information, (2) income statements, (3) balance sheets, (4) frequency distribution tables, (5) creative presentation.

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What physics is involved for a passenger feeling pushed backward into the seat of an airplane when it accelerates along the runw

timofeeve [1]

It's due to Inertia. The law of Inertia states that a body will try to retain its movement state if possible. This means, if a body is at rest, it will try to remain at rest using forces. Similarly, if it's in movement, it will try to remain in movement.

In this example, the plane is moving forwards, and so do the seats, which in turn push the passenger forwards.The force felt is Inertia acting on the body, trying to counter the movement.

7 0

3 years ago

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Write down an equation describing a sinusoidal traveling wave (in 1-D). Tell us (words and/or equations) what in your equation t

Natalija [7]

Answer:

Explanation:

The standard equation of the sinusoidal wave in one dimension is given by

$y = A Sin\left ( \frac{2\pi }{\lambda }\left ( vt-x \right )+\phi \right )$

Here, A be the amplitude of the wave

λ be the wavelength of the wave

v be the velocity of the wave

Φ be the phase angle

x be the position of the wave

t be the time

this wave is travelling along positive direction of X axis

The frequency of wave is f which relates with velocity and wavelength as given below

v = f x λ

The relation between the time period and the frequency is

f = 1 / T.

6 0

3 years ago

A model train engine was moving at a constant speed on a straight horizontal track. As the engine moved along, a marble was fir

bagirrra123 [75]

Answer:

The marble was moving in a projectile and the speed of the engine was 2.716 m/s

Explanation:

The vertical component of the marble's flight path relative to the train

is given by the equation y(t) = v*t - (4.9)*t^2,

where, v is the initial upward velocity of the marble relative to the train.

So with y(1) = v - 4.9 = 0 we have

v = 4.9 m/s.

The marble will reach maximum height after 0.5 seconds, at which the

height will be y(0.5) = (4.9)*(0.5) - (4.9)*(0.5)^2 = (4.9)*(0.25) = 1.225 m.

Now, the marble has a vertical velocity component of 4.9 m/s and a horizontal velocity component

of V m/s such that tan(61) = 4.9 / V

V = 4.9 / tan(61) = 2.716 m/s

This horizontal velocity component of the marble is the same as the

speed of the train i.e. 2.716 m/s.

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3 years ago

Which will a positively charged objects attract

Vitek1552 [10]

Me and you! enjoy your day girllllaa or boy

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3 years ago

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The area of an equilaterla triangle is increasing at a rate of 5 m^2/hr. find the rate at witch the height is chganging when the

Lena [83]

The rate at which the height is changing is ( 5 / x ) m / hr

We know that,

Area of an equilateral triangle A = $\sqrt{3}$ $x^{2}$ / 4

h = $\sqrt{3}$ x / 2

Where,

x = Side

h = Height

Given that,

dA / dt = 5 $m^{2}$ / hr

h = $\sqrt{3}$ x / 2

Differentiate both sides with respect to t

dh / dt = ( $\sqrt{3}$ / 2 ) ( dx / dt )

dx / dt = ( 2 / $\sqrt{3}$ ) ( dh / dt )

A = $\sqrt{3}$ $x^{2}$ / 4

Differentiate both sides with respect to t

dA / dt = ( $\sqrt{3}$ / 4 ) ( 2x ) ( dx / dt )

5 = ( $\sqrt{3}$ / 4 ) ( 2x ) ( 2 / $\sqrt{3}$ ) ( dh / dt )

dh / dt = ( 5 / x ) m / hr

Rate of change of height is defined as the rate at which height of an object changes with respect to time. It is represented as dh / dt

Therefore, the rate at which the height is changing is ( 5 / x ) m / hr

To know more about Rate of change of height

brainly.com/question/13283964

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1 year ago