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Bogdan [553]
4 years ago
11

Two different blocks of ice sit on the level floor of a meat packing plant. Yasmeen pushes with a horizontal force of magnitude

F on the first block, which has mass m, and it accelerates along the floor with acceleration magnitude a. She then pushes with horizontal force 2F on the second block, and it accelerates along the floor with acceleration magnitude 2a/3. What is the mass of the second block
Physics
1 answer:
vlada-n [284]4 years ago
4 0

Answer:

The mass is m_1 =  3m

Explanation:

Generally from Newton law for the first block

F = ma

=>    a =  \frac{F}{m}  

For the second block the force is  F_1 =  2F  and the acceleration is  a_1 = \frac{2a}{3}

So  from Newton law

      2F = m_1*\frac{2a}{3}  

=>   3F  =  m_1 * a

substituting for a

=>    3F  =  m_1 * \frac{F}{m}

=>    m_1 =  3m

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Answer:

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Explanation:

First, we will find the mass of the water:

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Mass = m = (1 kg/L)(10 L)

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Now, we will find the energy required to heat the water between given temperature limits:

E = mCΔT

where,

E = energy = ?

C = specific heat capacity of water = 4182 J/kg.°C

ΔT = change in temperature = 95°C - 25°C = 70°C

Therefore,

E = (10 kg)(4182 J/kg.°C)(70°C)

E = 2.927 x 10⁶ J

Now, the power required will be:

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where,

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At t = 0, one toy car is set rolling on a straight track with initial position 13.0 cm, initial velocity -3.6 cm/s, and constant
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Answer:

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3 years ago
A body weights 50 N in air and 45 N when wholly immersed in water calculate (i) the loss in weight of the body in water (ii) the
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Answer:

difference  \: in \: weight = 150n - 100n = 50n

Now,buyantant force

difference \: in \: weight \: = volume(body) \times density \: of \: water \:  \times g

so;

50 =  {v}^{b}  \times 1 \times  {10}^{3}  \times 9.8m {s}^{2}

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=  \frac{50}{9800}

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density =  \frac{weght}{volume}

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And now,

specific \: density \:  =  \frac{density of \: the \: body}{density \: of \: water}

=  \frac{3000}{1000}

= 3

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Answer:

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