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Bogdan [553]
3 years ago
11

Two different blocks of ice sit on the level floor of a meat packing plant. Yasmeen pushes with a horizontal force of magnitude

F on the first block, which has mass m, and it accelerates along the floor with acceleration magnitude a. She then pushes with horizontal force 2F on the second block, and it accelerates along the floor with acceleration magnitude 2a/3. What is the mass of the second block
Physics
1 answer:
vlada-n [284]3 years ago
4 0

Answer:

The mass is m_1 =  3m

Explanation:

Generally from Newton law for the first block

F = ma

=>    a =  \frac{F}{m}  

For the second block the force is  F_1 =  2F  and the acceleration is  a_1 = \frac{2a}{3}

So  from Newton law

      2F = m_1*\frac{2a}{3}  

=>   3F  =  m_1 * a

substituting for a

=>    3F  =  m_1 * \frac{F}{m}

=>    m_1 =  3m

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Answer:

a) X = 17.64 m

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Explanation:

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c) ∆X is the difference between position at t = 2.10s and t = 2.10 + ∆t so,

                 ∆X= 4∆t^2 + 16.8∆t

Divide by ∆t on both sides:  

                ∆X/∆t =  4∆t + 16.8

 Taking the limit as ∆t approaches to zero we get:  

              Velocity =lim(∆t→0)⁡〖∆X/∆t〗 = 4(0) + 16.8

              Velocity = 16.8 m/s

 

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