Sorry I had the answer but it wont let me type numbers :(.:
Answer:
m = 4
Explanation:
It is given that,
A 100 Newton force applied to a machine lifts a 400 N object.
We need to find the mechanical advantage of this machine.
The mechanical advantage of a machine is given by the ratio of output force to the input force.
Here, output force is 400 N and input force is 100 N
So, mechanical advantage becomes :
So, the mechanical advantage of this machine is 4.
Answer:
a) 1250 J
b) 17.9 m
Explanation:
Convert horsepower to watts:
0.12 HP = 89.5 W
a) Work = power × time
W = (89.5 W) (14 s)
W = 1250 J
b) Work = force × distance
1250 J = (70 N) d
d = 17.9 m
Answer:
0N
Explanation:
Parameters given:
Q1 = Q2 = Q3 = 100 * 10^(-9) C
r = 0.3 m
The net force on the middle charge is:
F = F(1,2) + F(2,3)
Where F(1,2) = force due to Q1 on Q2
F(2,3) = force due to Q3 on Q2
F(1,2) = k*Q(1)*Q(2)/r²
F(1,2) = [9 * 10^9 * 100 * 10^(-9) * 100 * 10^(-9)]/(0.3²)
F(1,2) = 0.001N
F(2,3) = k*Q(2)*Q(3)/r²
F(2,3) = [9 * 10^9 * 100 * 10^(-9) * -100 * 10^(-9)]/(0.3²)
F(2,3) = -0.001N
Therefore,
F = 0.001 - 0.001
F = 0N
Answer:
Explanation:
pV = nrT
n = PV/RT
n = (100*10^3)(.01)/(300*0.082057)
n = 40.62 moles
