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vazorg [7]
3 years ago
9

Which of the following could be a step in a plan designed to mitigate the negative impacts of a natural hazard? I. design new te

chnologies to protect people when a natural hazard occurs II. prevent natural hazards, such as tornadoes and earthquakes, from occurring III. design new technologies to monitor and predict natural hazards IV. design warning and evacuation systems
Physics
2 answers:
erastova [34]3 years ago
7 0
Designing warning and evacuation systems could be a step in a plan designed to mitigate the negative impacts of a natural hazard.
cupoosta [38]3 years ago
5 0

Answer: The answer is A

Explanation:

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Food has calories which feeds your bones in your body from eating away your muscles, it doesn’t have “energy” on the other hand pop and drinks do.
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3 years ago
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A 30.0 kg box hangs from a rope. What is the tension (in N) in the rope if the box has an initial velocity of 2.0 m/s and is slo
hjlf

Answer:

360 N

Explanation:

m = 30kg    u = 2 m/s     a = -2m/s/s

Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s

the object will come to rest in 1 second but the force applied in that one second can be calculated by:

F = ma

F = 30 * -2

F = -60 N (the negative sign tells us that the force is acting downwards)

Now, calculating the force applied on the box due to gravity

letting g = -10m/s/s

F = ma

F = 30 * -10

F = -300 N (the negative sign tells us that the force is acting downwards)

Now, calculating the total downward force:

-300 + (-60) = -360 N

<em></em>

<em>Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction</em>

Therefore tension on the force = <u>360 N</u>

5 0
4 years ago
11. Will the cube in#10 float in water? Will it float in benzene?
densk [106]
Where is the cube I don't see any picture?
5 0
3 years ago
A locomotive accelerates a 25-car train along a level track. Every car has a mass of 7.7 ✕ 104 kg and is subject to a friction f
MaRussiya [10]

To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.

In this way,

The total mass of the cars would be,

m_T = 25(7.7*10^4)Kg

m_T = 1.925*10^6Kg

Therefore the friction force at 29Km / h would be,

f=250v

f= 250*29Km/h

f = 250*29*(\frac{1000m}{1km})(\frac{1h}{3600s})

f = 2013.889N

In this way the tension exerts between first car and locomotive is,

T=m_Ta+f

T=(1.925*10^6)(0.2)+2013.889

T= 3.8701*10^5N

Therefore the tension in the coupling between the car and the locomotive is 3.87*10^5N

6 0
3 years ago
I DO NOT WANT LINKES OR …………..
il63 [147K]

1st B is correct option

2nd D is correct option

4 0
3 years ago
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