The formula of Iron(III) oxide is Fe2O3
In order to calculate the mass of iron in a given sample of iron(III) oxide, we must first know the mass percentage of iron in iron(III) oxide. This is calculated by:
[mass of iron in one mole of iron(III) oxide/ mass of one mole of iron(III) oxide] * 100
= [(moles of iron * Mr of iron) / (moles of Iron * Mr of Iron + moles of Oxygen * Mr of Oxygen)] * 100
= [(2 * 56) / (2 * 56 + 3 * 16)] * 100
= (112 / 160) * 100
= 70%
Thus, in a 100g sample, the weight of iron will be:
100 * 70%
= 70 grams
First of all, you should know the valence electron of atom.
Then add charge, In case of -ve ion & subtract, in case of +ve ion.
Answer:
10 moles de NO2
Explanation:
Tenemos la ecuación de la reacción como sigue;
N2 (g) + 2 O2 (g) → 2 NO2 (g)
Asi que;
Si 1 mol de nitrógeno produce 2 moles de NO2
5 moles de nitrógeno producirán 5 * 2/1 = 10
Por tanto, se producen 10 moles de NO2 moles
