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Snezhnost [94]
3 years ago
8

Can you guys help to understand this graph I'm so confused why I getting wrong?

Physics
2 answers:
dedylja [7]3 years ago
4 0
The one fact that needs to be mentioned but isn't given anywhere on or around the graph is: The distance, on the vertical axis, is the distance FROM home. So any point on the graph where the distance is zero ... the point is in the x-axis ... is a point AT home.

Segment D ...
Walking AWAY from home; distance increases as time increases.

Segment B ...
Not walking; distance doesn't change as time increases.

Segment C ...
Walking away from home, but slower than before; distance increases as time increases, but not as fast. Slope is less than segment-D.

Segment A ...
Going home; distance is DEcreasing as time increases. Walking pretty fast ... the slope of the line is steep.
Archy [21]3 years ago
4 0
Thanks for the question!

A would be walking away from home because the distance is going down.

B would be not walking because the distance is staying constant.

C would be walking slowly because the slope is small.

D would be walking quickly because the slope is large.

Hope this helps!
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2 years ago
A football field is about 100 m long. If it takes a person 20 seconds to run its length, how fast (what speed) were they running
leonid [27]

Answer:

Speed, v = 5 m/s

Explanation:

We have,

The length of the football field, l = 100 m  

A person takes 20 seconds to run its length.

It is required to find the speed of the person with which he should run. The distance covered divided by time taken is called its velocity.

v=\dfrac{d}{t}\\\\v=\dfrac{100\ m}{20\ s}\\\\v=5\ m/s

So, the speed of the person is 5 m/s.

3 0
4 years ago
A girl and her bicycle have a total mads of 42 kg. At the top of the hill her speed is 4 m/s. The hill is 14.3m high and 112m lo
frosja888 [35]

Answer:

13.78 m/s

Explanation:

Given that:

The mass of the girl & her bicycle = 42 kg

The speed at the top of the hilll= 4 m/s

The height of the hill = 14.3 m

The length of the hill (distance) = 112 m

The frictional force = 20 N

To find the speed at the bottom of the hill; we need to carry out the following processes.

The workdone by gravity = mass × acceleration due to  gravity × Δh

= 42 × 9.8 × ( 14.3 - 0 )

= 5885.88 joules

The workdone by the friction = Force × distance = - 20 × 112    (since she is riding down the hill)

The workdone by the friction = -2240 Joules

The initial Kinetic friction = 1/2 mv²

= 1/2 × 42 × 4²

= 336 Joules

The final kinetic energy = Initial Kinetic energy + total work  

The final kinetic energy = (336 + 5885.88 - 2240) Joules

The final kinetic energy = 3981.88   Joules

Using the final kinetic energy =   1/2 mv²

3981.88  = 1/2 × 42 × v²

3981.88  = 21 v²

v² = 3981.88/21

v² =189.61

v = \sqrt{189.61}

v = 13.78 m/s

Therefore, the speed at the bottom = 13.78 m/s

4 0
3 years ago
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HOPE THIS HELPS YOU!!!!!

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ipn [44]

A). force

hope it helps and your day will be full of happiness

4 0
3 years ago
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