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Snezhnost [94]
2 years ago
8

Can you guys help to understand this graph I'm so confused why I getting wrong?

Physics
2 answers:
dedylja [7]2 years ago
4 0
The one fact that needs to be mentioned but isn't given anywhere on or around the graph is: The distance, on the vertical axis, is the distance FROM home. So any point on the graph where the distance is zero ... the point is in the x-axis ... is a point AT home.

Segment D ...
Walking AWAY from home; distance increases as time increases.

Segment B ...
Not walking; distance doesn't change as time increases.

Segment C ...
Walking away from home, but slower than before; distance increases as time increases, but not as fast. Slope is less than segment-D.

Segment A ...
Going home; distance is DEcreasing as time increases. Walking pretty fast ... the slope of the line is steep.
Archy [21]2 years ago
4 0
Thanks for the question!

A would be walking away from home because the distance is going down.

B would be not walking because the distance is staying constant.

C would be walking slowly because the slope is small.

D would be walking quickly because the slope is large.

Hope this helps!
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Green light (λ = 518 nm) strikes a single slit at normal incidence. What width slit will produce a central maximum that is 3.00
MariettaO [177]

Answer:

6.9066 × 10⁻⁵ m

Explanation:

For constructive interference, the expression is:

d\times sin\theta=m\times \lambda

Where, m = 1, 2, .....

d is the distance between the slits.

The formula can be written as:

sin\theta=\frac {\lambda}{d}\times m ....1

The location of the bright fringe is determined by :

y=L\times tan\theta

Where, L is the distance between the slit and the screen.

For small angle , sin\theta=tan\theta

So,  

Formula becomes:

y=L\times sin\theta

Using 1, we get:

y=L\times \frac {\lambda}{d}\times m

Thus, the distance between the central maximum is 3.00 cm

First bright fringe , m = 1 occur at 3.00 / 2 = 1.50 cm

Since,

1 cm = 0.01 m

y = 0.0150 m

Given L = 2.00 m

λ = 518 nm

Since, 1 nm = 10⁻⁹ m

So,

λ = 518 × 10⁻⁹ m

Applying the formula as:

0.0150\ m=2.00\ m\times \frac {518\times 10^{-9}\ m}{d}\times 1

<u>⇒ d, distance between the slits = 6.9066 × 10⁻⁵ m</u>

7 0
2 years ago
Groups of students are making measurements of small cars rolling across a table. the class has measuring tapes with markings in
TiliK225 [7]

To find the accurate measurement of small cars, the teacher asks students to make all the measurements in centimeters.

Centimeters Measurements:

  • A centimeter is a metric unit of measurement used for measuring the length of an object, It is written as cm
  • Centimeter is one hundredth of a meter, 1 meter is 0.01 cm.

Inches measurements:

  • An inch can be defined as a unit of length in the customary system of measurement. Length in inches is either represented by in or ''.
  • 1 meter is equal to 39.37 inches

here, the cars are small objects.

The number of centimeters is always bigger,

because a centimeter unit is smaller than an inch unit, and it takes more of them when we are measuring.

Hence,

To find the accurate measurement of small cars, the teacher asks students to make all the measurements in centimeters.

Learn more about accurate measurement here:

<u>brainly.com/question/4119127</u>

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There are no risks when taking medication to treat anxiety.
lidiya [134]

Answer:

False

Explanation:

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What does the first law of thermodynamics state about energy?
ruslelena [56]

The first law states that the internal energy change of that system is given by Q − W . Since added heat increases the internal energy of a system, Q is positive when added to the system and negative when removed from the system.

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If the wave being sent is transmitted via an electromagnetic wave explain how the digital signal would be perceived if the signa
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Answer:

amplitude is commonly for transmitting messages with a radio carrier wave, the amplitude (signal strength) of the carrier wave is varied in proportion to that of the message signal. at the receiving end, the message signal is extracted from the modulated carrier by demodulation. frequency is the encoding of information in a carrier wave with instantaneous frequency. with digital data, the frequency of the carrier is shifted among a set of frequencies, using digits like 1 and 0

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