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Snezhnost [94]
3 years ago
8

Can you guys help to understand this graph I'm so confused why I getting wrong?

Physics
2 answers:
dedylja [7]3 years ago
4 0
The one fact that needs to be mentioned but isn't given anywhere on or around the graph is: The distance, on the vertical axis, is the distance FROM home. So any point on the graph where the distance is zero ... the point is in the x-axis ... is a point AT home.

Segment D ...
Walking AWAY from home; distance increases as time increases.

Segment B ...
Not walking; distance doesn't change as time increases.

Segment C ...
Walking away from home, but slower than before; distance increases as time increases, but not as fast. Slope is less than segment-D.

Segment A ...
Going home; distance is DEcreasing as time increases. Walking pretty fast ... the slope of the line is steep.
Archy [21]3 years ago
4 0
Thanks for the question!

A would be walking away from home because the distance is going down.

B would be not walking because the distance is staying constant.

C would be walking slowly because the slope is small.

D would be walking quickly because the slope is large.

Hope this helps!
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Can someone give me tips to passing AP Physics 1 with a solid A? Like, tips on how to memorize a lot of equations? Thank you!
Anna007 [38]
A good way for me to remember things is to study it, and to write it down! Say you want the formula for speed, I would write the formula multiple times on a piece of paper! 

Here's a video that I haven't actually watched, I just looked it up! It might help you out though: <span>https://www.youtube.com/watch?v=-Wqrw4G79Kc</span>
3 0
3 years ago
An airplane is heading due south at a speed of 430 km/h . A wind begins blowing from the northwest at a speed of 85.0 km/h (aver
Igoryamba

Answer:

It should fly 8° to west of south at 430km/h

Explanation:

According to the diagram. X components for both velocities must have the same magnitude in order to get the resultant velocity due south.

V_{w}*cos(45) = V_{A}*sin(\alpha )   Solving for α:

α = 8.03°

5 0
2 years ago
A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is
aivan3 [116]
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4 0
3 years ago
Read 2 more answers
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solniwko [45]
The water was heavier since it was more concentrated


8 0
3 years ago
(i) Calculate the energy, in electron volts, of a photon whose frequency is (a) 620 THz}, (b) 3.10GHz , and(c) 46.0 MHz
DedPeter [7]

The energy in electron volts of the photons that has the following frequencies is as follows:

  1. 620 THz = 2.564eV
  2. 3.10GHz = 1.28 × 10-⁵eV
  3. 46.0 MHz = 1.902 × 10-⁷eV

<h3>How to calculate energy?</h3>

The energy of a photon can be calculated using the following formula:

E = hf

Where;

  • E = energy
  • h = Planck's constant (6.626 × 10-³⁴ J/s)
  • f = frequency

First, we convert the frequencies to hertz as follows;

  • 620THz = 6.2 × 10¹⁴Hz
  • 3.10GHz = 3.1 × 10⁹Hz
  • 46.0MHz = 4.6 × 10⁷Hz

  1. E = 6.626 × 10-³⁴ × 6.2 × 10¹⁴ = 2.564eV
  2. E = 6.626 × 10-³⁴ × 3.1 × 10⁹ = 1.28 × 10-⁵eV
  3. E = 6.626 × 10-³⁴ × 4.6 × 10⁷ = 1.902 × 10-⁷eV

Learn more about energy of a photon at: brainly.com/question/2393994

#SPJ1

6 0
1 year ago
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