Answer:
![=5r^2-17r+5](https://tex.z-dn.net/?f=%3D5r%5E2-17r%2B5)
Step-by-step explanation:
![\mathrm{Apply\:rule}:\quad \left(a\right)=a](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Arule%7D%3A%5Cquad%20%5Cleft%28a%5Cright%29%3Da)
![\left(8r^2-12r+4\right)=8r^2-12r+4](https://tex.z-dn.net/?f=%5Cleft%288r%5E2-12r%2B4%5Cright%29%3D8r%5E2-12r%2B4)
![=8r^2-12r+4-\left(3r^2+5r-1\right)](https://tex.z-dn.net/?f=%3D8r%5E2-12r%2B4-%5Cleft%283r%5E2%2B5r-1%5Cright%29)
![\mathrm{Apply\:the\:distributive\:law}:\quad \:-\left(a+b\right)=-a-b](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Athe%5C%3Adistributive%5C%3Alaw%7D%3A%5Cquad%20%5C%3A-%5Cleft%28a%2Bb%5Cright%29%3D-a-b)
![-\left(3r^2+5r-1\right)=-3r^2-5r+1](https://tex.z-dn.net/?f=-%5Cleft%283r%5E2%2B5r-1%5Cright%29%3D-3r%5E2-5r%2B1)
![=8r^2-12r+4-3r^2-5r+1](https://tex.z-dn.net/?f=%3D8r%5E2-12r%2B4-3r%5E2-5r%2B1)
![\mathrm{Group\:like\:terms}](https://tex.z-dn.net/?f=%5Cmathrm%7BGroup%5C%3Alike%5C%3Aterms%7D)
![=8r^2-3r^2-12r-5r+4+1](https://tex.z-dn.net/?f=%3D8r%5E2-3r%5E2-12r-5r%2B4%2B1)
![\mathrm{Add\:the\:numbers:}\:4+1=5](https://tex.z-dn.net/?f=%5Cmathrm%7BAdd%5C%3Athe%5C%3Anumbers%3A%7D%5C%3A4%2B1%3D5)
![=8r^2-3r^2-12r-5r+5](https://tex.z-dn.net/?f=%3D8r%5E2-3r%5E2-12r-5r%2B5)
![\mathrm{Add\:similar\:elements:}\:8r^2-3r^2=5r^2](https://tex.z-dn.net/?f=%5Cmathrm%7BAdd%5C%3Asimilar%5C%3Aelements%3A%7D%5C%3A8r%5E2-3r%5E2%3D5r%5E2)
![=5r^2-12r-5r+5](https://tex.z-dn.net/?f=%3D5r%5E2-12r-5r%2B5)
![\mathrm{Add\:similar\:elements:}\:-12r-5r=-17r](https://tex.z-dn.net/?f=%5Cmathrm%7BAdd%5C%3Asimilar%5C%3Aelements%3A%7D%5C%3A-12r-5r%3D-17r)
![=5r^2-17r+5](https://tex.z-dn.net/?f=%3D5r%5E2-17r%2B5)
They meet their median goal because if you rearrange the numbers from lowest to highest, the median mileage of their line of cars would be 19,23,25,26,29. There are five numbers of car mileages therefore 25 would serve as the median for all five mileages.
Answer:
Step-by-step explanation:
The answer is -48 ,
3x4(-4)=
12(-4)=
-48
Answer: 81pi square meters
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Work Shown
C = 18pi is the given circumference
d = diameter which is unknown
C = pi*d
18pi = pi*d
18 = d
d = 18
The diameter is 18 meters.
Half of this is the radius r = d/2 = 18/2 = 9
The radius is 9 meters
Use the value of r to find the area of the circle
A = pi*r^2
A = pi*9^2
A = pi*81
A = 81pi
The area of the circular cross section is 81pi square meters