A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is (
).
Utilize the titration method of in view that we're given the concentrations of every compound and the quantity of 
. Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.
- M1 = initial mass
- V1= initial volume
- M2 = final mass
- V2= final volume
- (0.138)(V1) = (0.205)x(26.0)
- V2=(0.205)x(26.0)\ 0.138
- V2 = 47.10 M/L
- The final value of Volume needed for neutralization of nitric acid solution is V2 = 47.10 M/L
Read more about the neutralization:
brainly.com/question/23008798
#SPJ4
Answer:
Explanation:
diffusion has already occurred
Here we apply the Clausius-Clapeyron equation:
ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁)
The normal vapor pressure is 4.24 kPa (P₁)
The boiling point at this pressure is 293 K (P₂)
The heat of vaporization is 39.9 kJ/mol (ΔH)
We need to find the vapor pressure (P₂) at the given temperature 355.3 K (T₂)
ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293)
P₂ = 101.2 kPa
J.j Thomson electrons demo true indivisible sphere n Ernest central nucleas
<span>The mole fraction of oxygen gas is 2/6 =1/3, because there are 6 total moles of gas in the container. The partial pressure can be found by multiplying this mole fraction by the total pressure. So the answer is B. 262 kPA because 1/3(786)=262.</span>
