Help me please I beg you
2 answers:
Answer:
Neither
Step-by-step explanation:
We need to transform one of the equations into its slope-intercept form:
y + 2/5x = 8
Subtract 2/5x from both sides:
y = -2/5x + 8
y = -5/2x - 7
Graphing both lines, they do intersect at point (-7.14, 10.86), but they are not parallel, nor are they perpendicular from each other. By definition, perpendicular lines must appear to be perpendicular (that is, they intersect at a 90° angle).
Looking at the attached graph (where the purple line is y = -2/5x + 8), their lines do not form a 90° angle.
Therefore, the correct answer is neither.
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From the given information, a exists jointly proportional to b and c.
then
Therefore, the value of a exists 2.
<h3>What is the value of a?</h3>Given, a exists jointly proportional to b and c.
Taking K as the constant of proportionality.
a = K b c
For b = 8 and c = 9, the value of a = 4
4 = K(8)(9)
4 = 72 K
Dividing the equation by 72, we get
Using the value of K in the equation:
Substitute the values of b = 2 and c = 18, in the above equation
a = 2
Therefore, the value of a exists 2.
To learn more the value of x refers to:
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