Answer:
Answer of question a is 345J.
Explanation:
In question a following is given in data:
-mass of iron (m) = 10.0 g
-temperature (ΔT) = final temperature- initial temperature= 100-25= 75 degree Celsius
-Specific Heat capacity of iron (c)= 0.46J/g°C.
Heat (Q)=?
Solution:
Formula for Heat is :
Q=m x c x ΔT
Q= 10 x 0.46 x 75
Q= 345 J.
so, 345 joules of heat is needed to increase the temperature of 10 grams of iron.
- From the above formula all other questions can easily be solved from the same procedure.
Solute=potassium chloride, solvent=water
I think you meant K as in kilograms?
If so, the answer should be 0.0052.
day and night is the main way you can tell as well as the stars moving across the sky, and we can tell it rotates by looking at the sky and seeing the sun move across the sky during the day.
4:2. You are comparing the coefficients of NH3 and N2