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Juli2301 [7.4K]
3 years ago
10

a compound had a molecular weight of 112.124 atomic mass units and the empirical formula C3H4O what is the molecular formula of

the compound?
Chemistry
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer : The molecular of the compound is, C_6H_8O_2

Solution : Given,

Molecular weight of compound = 112.124 amu

The Empirical formula = C_3H_4O_1

First we have to calculate the empirical formula weight.

The empirical formula weight = 12(3) + 4(1) + 1(16) = 56 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}\\\\n=\frac{112.124}{56}=2

Molecular formula = (C_3H_4O_1)_n=(C_3H_4O_1)_2=C_6H_8O_2

Therefore, the molecular of the compound is, C_6H_8O_2

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<h3>What is molar concentration?</h3>

The phrase "molar concentration" (also known as "molarity," "amount concentration," or "substance concentration") refers to the amount of a substance per unit volume of solution and is used to describe the concentration of a chemical species, specifically a solute, in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units. A solution with a concentration of 1 mol/L is referred to as 1 molar, or 1 M.

<h3>Given : </h3>

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<h3>Formula use: </h3>

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