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Juli2301 [7.4K]

3 years ago

10

a compound had a molecular weight of 112.124 atomic mass units and the empirical formula C3H4O what is the molecular formula of

the compound?

1 answer:

Snowcat [4.5K]3 years ago

8 0

Answer : The molecular of the compound is, $C_6H_8O_2$

Solution : Given,

Molecular weight of compound = 112.124 amu

The Empirical formula = $C_3H_4O_1$

First we have to calculate the empirical formula weight.

The empirical formula weight = 12(3) + 4(1) + 1(16) = 56 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}\\\\n=\frac{112.124}{56}=2$

Molecular formula = $(C_3H_4O_1)_n=(C_3H_4O_1)_2=C_6H_8O_2$

Therefore, the molecular of the compound is, $C_6H_8O_2$

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What is galvanization ?

zheka24 [161]

Explanation:

The most common hot dipping process for industrial applications is galvanizing, which refers to the coating of zinc over iron or steels for rust proofing. It is an extremely versatile and easy means of providing corrosion protection for construction materials exposed to atmospheric conditions

6 0

3 years ago

The partial pressure of in your lungs varies from 25 mm Hg to 40 mm Hg. What mass of can dissolve in 1.0 L of water at 25 °C if

Sonja [21]

The question is incomplete. The complete question is:

The partial pressure of $O_2$ in your lungs varies from 25 mm Hg to 40 mm Hg. What mass of $O_2$ can dissolve in 1.0 L of water at 25 degree Celsius if the partial pressure of $O_2$ is 40 mm Hg.

Answer: $2.12\times 10^{-3}g$

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{O_2}=K_H\times p_{O_2}$

where,

$K_H$ = Henry's constant = $1.30\times 10^{-3}mol/Latm$

$p_{O_2}$ = partial pressure = 39 mm Hg = 0.051 atm (760mmHg=1atm)

Putting values in above equation, we get:

$C_{O_2}=1.30\times 10^{-3}mol/Latm\times 0.051atm\\\\C_{O_2}= 6.63\times 10^{-5}mol/L$

$C_{O_2}=6.63\times 10^{-5}mol/L\times 32g/mol=2.12\times 10^{-3}g$

Hence, $2.12\times 10^{-3}g$ of $O_2$ can dissolve in 1.0 L of water at 25 °C if the partial pressure of is 39 mm Hg

8 0

3 years ago

C) A standard cubic foot of natural gas carries with it about 1.1 x 106 J of energy. Natural gas currently costs about $16.25 pe

pochemuha

Answer:

67692.31 J

396811.337 J

Explanation:

(a) The cost of standard cubic foot of natural gas = $16.25

The energy related to standard cubic foot of natural gas = $1.1\times 10^{6}\ J$

Thus, As according to the question,

$16.25 of natural gas have $1.1\times 10^{6}\ J$ of energy.

$1 of natural gas have $\frac{1.1\times 10^{6}}{16.25}\ J$ of energy.

<u>The amount of energy = 67692.31 J</u>

(b) The cost of one short ton of coal = $56.45

The energy related to the short ton of coal = $2.24\times 10^{7}\ J$

Thus, As according to the question,

$56.45 of coal have $2.24\times 10^{7}\ J$ of energy.

$1 of coal have $\frac{2.24\times 10^{7}}{56.45}\ J$ of energy.

<u>The amount of energy = 396811.337 J</u>

<u></u>

6 0

3 years ago

If the fugacity coefficient of the components of a binary mixture are = 0.784, and =0.638 and mole fraction of component 1 is 0.

Reika [66]

Answer : The expression for the fugacity coefficient $\ln \phi$ , for the mixture is, -0.3669.

Explanation : Given,

Fugacity coefficient of component 1 = 0.784

Fugacity coefficient of component 2 = 0.638

Mole fraction of component 1 = 0.4

First we have to calculate the mole fraction of component 2.

As we know that,

$\text{Mole fraction of component 1}+\text{Mole fraction of component 2}=1$

$\text{Mole fraction of component 2}=1-0.4=0.6$

Now we have to calculate the expression for the fugacity coefficient $\ln \phi$ .

Expression used :

$\ln \phi=X_1\ln \phi_1+X_2\ln \phi_2$

where,

$\phi$ = fugacity coefficient

$\phi_1$ = fugacity coefficient of component 1

$\phi_2$ = fugacity coefficient of component 2

$X_1$ = mole fraction of of component 1

$X_2$ = mole fraction of of component 2

Now put all the give values in the above expression, we get:

$\ln \phi=0.4\times \ln(0.784)+0.6\times \ln(0.638)$

$\ln \phi=-0.3669$

Therefore, the expression for the fugacity coefficient $\ln \phi$ , for the mixture is, -0.3669.

7 0

3 years ago

A teacher has asked some groups of students to investigate the relationship between the organ systems of the human body. One gro

liberstina [14]

Answer: The digestive system breaks down food into nutrients that are transported by the circulatory system.

Explanation:

An organ system includes the organs which are linked to one another to perform a physiological function in the body of the organism. The digestion is a complex process in which the food is being broken down into sub-components so that it can be assimilated in the body. The digestive system involves the multiple organs like mouth, esophagus, stomach, intestines and others. The food being digested is absorbed in the bloodstream, which circulate in the vital organs of the body like lungs, heart, vascular system hence, the blood becomes the part of the circulatory system.

Thus it can be said that the argument of children that the two systems are related is justified by the digestive and circulatory system of the body.

5 0

3 years ago