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Georgia [21]
3 years ago
9

Can somebody please help me

Engineering
1 answer:
astraxan [27]3 years ago
6 0

Answer:

C. 420 x 594 millimeters

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nirvana33 [79]

Answer:

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B. 4WD High

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4 0
3 years ago
While driving down the highway, your car must overcome the forces of friction and air resistance in order to keep the car moving
ElenaW [278]

Answer:

Efficiency of the engine equals 20%

Explanation:

We know that when the car moves it must do work against the resisting forces to keep moving and this work is spend as energy by the engine to keep the car moving.

we know that

Work=Force\times Displacement

Thus to keep the car moving for 100,000 meters the theoretical work that requires to be done equals  

Work=560N\times 100,000m=56\times 10^{6}Joules

Now the actual energy spend by the car equals the energy spend by burning 2.8 gallons of gasoline.

Thus the energy produced by burning 2.8 gallons of gasoline equals

2.8\times 100\times 10^{6}=280\times 10^{6}Joules

Thus the efficiency is calculated as

\eta =\frac{56\times 10^{6}}{280\times 10^{6}}\times 100\\\\\therefore \eta =20percent

5 0
3 years ago
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