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Vera_Pavlovna [14]
4 years ago
14

A student put together the experimental setup shown below. The selectively permeable membrane is permeable to water, but not the

solute shown.
Over time, what will happen in this system?
No change will take place.
Water will move from left to right.
Water will move from right to left.
Solute will move from right to left.
Chemistry
2 answers:
Galina-37 [17]4 years ago
8 0
The correct answer to this question is Water will move from left to right.

Water tends to move over to the side where there is less water. For example, if there's less water on the RIGHT side, then the water will tend to move from left, to RIGHT. It <span>shows more solute molecules on the right, so water will move to this side by osmosis. I think it is to do with entropy and the tendency for systems to move to equilibrium if there is an increase in entropy</span>
e-lub [12.9K]4 years ago
7 0
I believe water will move from left to right in this system.
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Given that 242.2J of energy is required to heat 81.6g of copper from 27.5°C to 35.2°C, find the specific heat of copper.
nikdorinn [45]

Answer:

c = 0.39 J/g.°C

Explanation:

Given data:

Energy required = 242.2 J

Mass of copper = 81.6 g

Initial temperature = 27.5°C

Final temperature = 35.2°C

Specific heat capacity of copper = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 35.2°C -  27.5°C

ΔT = 7.7°C

242.2 J = 81.6 g ×c ×  7.7°C

242.2 J / 81.6 g = c ×  7.7°C

c = 3 J/7.7g.°C

c = 0.39 J/g.°C

6 0
3 years ago
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How do you determine which tool to use for lab activities?
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But, if you were looking for what it would be called it would be:

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I wasn’t sure of your question so I answered the best way that I could. I hope this helped!
4 0
3 years ago
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