Answer:
pKa of the acid HA with given equilibrium concentrations is 6.8
Explanation:
The dissolution reaction is:
HA ⇔ H⁺ + A⁻
So at equilibrium, Ka is calculated as below
Ka = [H⁺] x [A⁻] / [HA] = 2.00 x 10⁻⁴ x 2.00 x 10⁻⁴ / 0.260
= 15.38 x 10⁻⁸
Hence, by definition,
pKa = -log(Ka) = - log(15.38 x 10⁻⁸) = 6.813
Answer:
Explanation:
By the First Law of Thermodynamics, the piece of metal and water reaches thermal equilibrium when water receives heat from the piece of metal. Then:
Hi there!
p = e-3
s = f-1
f = i-7
d = g-5
Hope that helps!
Brady
Answer:
the value of the equilibrium constant Kp for this reaction is 0.275
Explanation:
Step 1: Data given
Pressure HCl at the equilibrium = 18.0 atm
Pressure H2 at the equilibrium = 25.4 atm
Pressure Cl2 at the equilibrium = 46.4 atm
Step 2: The balanced equation
H2(g) + Cl2(g) → 2 HCl(g)
Step 3: Calculate the value of the equilibrium constant Kp for this reaction
Kp = (pHCl)² / (pH2*pCl2)
Kp = 18.0² / (25.4 * 46.4)
Kp = 324 / 1178.56
Kp = 0.275
the value of the equilibrium constant Kp for this reaction is 0.275
