Make an observation.
Ask a question.
Form a hypothesis, or testable explanation.
Make a prediction based on the hypothesis.
Test the prediction.
Iterate: use the results to make new hypotheses or predictions. Hope this helps
1 mole of H2O weighs 18 g
therefore 13.8 g of liquid H2O = 13.8/18 moles
ΔHvaporization = 40.65 kJ/mol
heat required to change 13.8 grams of H2O from a liquid to a gas at 100 degrees Celsius = 40.65 x 13.8/18 = 31.165 kJ
The combustion reaction of acetylene has a balanced equation
C2H2+3O2--->2H2O+2CO2
Using the ratio 1:3:2:2, if 1.10 mols of CO2 are produced, assuming complete combustion, than that means that 0.55 mols of acetylene (C2H2) must have been combusted. The molar mass of acetylene is 26, so the answer is 26*0.55 = 14.3 grams
Answer:
Answer: The solubility of B is high than the solubility of A.
Explanation:
The solubility is defined as the amount of substance dissolved in a given amount of solvent. More the solute gets dissolved, high will be the solubility and less the solute dissolved, low will be the solubility.
Mass of undissolved substance of substance A is more than Substance B at every temperature. This implies that less amount of solute gets dissolved in the given amount of solvent.
Therefore, B has high solubility than substance A.
Answer:
your answer would be : examples such as Thallium-206, Lead-210, & Bismuth-214.