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umka2103 [35]
3 years ago
14

Light travels at a rate of 3.00 x 10^8 m/s. It takes light 8.30 min to travel from the surface of the sun to the earth. What is

the distance of the earth from the sun?
Chemistry
1 answer:
bija089 [108]3 years ago
7 0

Answer: The distance of the earth from the sun is 1.494\times 10^{11}m

Explanation:

Speed of light = 3.00\times 10 ^8 m/s

Time taken to travel from sun to earth = 8.30 mins = 8.3\times 60=498sec    (1min=60 s)

As we know ; Speed is defined as the distance travelled per unit time.

Distance=speed\times time

Hence distance between sun and earth =3.00\times 10^8m/s\times 498s=1.494\times 10^{11}m

Thus the distance of the earth from the sun is 1.494\times 10^{11}m

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Answer:

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Explanation:

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3 years ago
____________is not an effect of heat
devlian [24]

Answer:

c. contraction

Explanation:

Heating will cause substances to expand, or change their state (like solid to liquid) or it may be a chemical reaction.

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2 years ago
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Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The
Maksim231197 [3]

Answer:

           \large\boxed{\large\boxed{24.6kJ}}

Explanation:

<u>1. Energy to heat the liquid water from 55ºC to 100ºC</u>

     Q=m\times C\times \Delta T

  • m = 10.1g
  • C = 4.18g/JºC
  • ΔT = 100ºC - 55ºC = 45ºC

     Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J

<u>2. Energy to change the liquid to steam at 100ºC</u>

      L=\lambda \times n

  • λ = 40.6kJ/mol
  • n = 10.1g / 18.015g/mol = 0.5606mol

      L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J

<u>3. Total energy</u>

       1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ

7 0
3 years ago
How many grams are in 2.3 moles of N?
jok3333 [9.3K]
The amount of grams that are in 2.3 moles of N = 32.223 or 32/100
Because there are 14.01 grams per mile of nitrogen atoms.
So…
14.01 x 2.3= 32.223
Hope this helps :)
6 0
2 years ago
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What mass of K2SO4 would you measure out to prepare 550 ml of a 0.76 M solution
Nikolay [14]
The molecular weight of K2SO4 is 174.26 g/mole. The mass of K2SO4 required to make this solution is calculated in the following way. 
550mL * (0.76mole/1000mL) * (174.26g/mole) = 72.84gram
<span>I hope this helps.</span>
5 0
3 years ago
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