The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
<u>Step-by-step explanation:</u>
Let the speed of wind and speed of plane in still air are w and p km/h respectively.
The effective speed on onward journey was
................(1)
The effective speed on return journey was
..............(2)
Adding equation (1) and equation (2) we get,
⇒
⇒
⇒
Putting value of in we get:
⇒
⇒
⇒
Therefore ,The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
3+0.05+0.0009+0.000004. I'm pretty sure you can only write it in one way for expanded from, but you can also say Three and Fifty Thousand Nine Hundred Four Millionths
Answer:
x = 7, y = 6
Step-by-step explanation:
solve for y for the first equation
2x + y = 20
-2x -2x , eliminate 2x
y = 20-2x
now that we have found y, substitute the y in for the second equation
-5y = -6x + 12
-5(20-2x) = -6x + 12, we just changed y into 20-2x. remember that we are multiplying all of 20 - 2x by -5
-100+10x = -6x + 12, we multiplied everything from the parathesis by -5
+100 + 100, eliminate -100
10x = -6x + 112
+6x +6x , eliminate 6x
16x = 112 , solve for x
x = 7
then y = 20 - 2x = 20 - 2*7 = 6
check:
2 * 7 + 6 = 20
20 = 20
-5 * 6 = -6 * 7 + 12
-30 = -42 + 12
-30 = -30
Answer:
$14
Step-by-step explanation:
3.50/2= 1.75
1.75*8= 14