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3 years ago

Why is honesty especially important in a scientist when the results of an experiment go against predictions❓❔

1 answer:

kramer3 years ago

8 0

Because other scientists and science in general rely on their collegues' research which in turn allows development of our knowledge on the given subject. The more dont-to-earth reason may be safety. If someone performs an experiment without knowledge of its true results it might result in some danger to the safety of those perforning it without knowledge of all the risks.

You might be interested in

Four forces act at a point in the image above. calculate the resultant.

levacccp [35]

Answer:

50° and 60°

Explanation:

hope this help

3 0

3 years ago

A 80 kg block starts from rest at the top of a 15m frictionless ramp. The block slides down the frictionless ramp onto a rough h

Nadusha1986 [10]

Answer:

W(fric) = -12000 J

Explanation:

Given that

mass ,m= 80 kg

Initial speed ,u= 0 m/s

Height ,h= 15 m

Final speed ,v= 0 m/s

We know that

Work done by all the forces = Change in the kinetic energy

$W_{gravity}+W_{fric}=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2$

$W_{gravity}+W_{fric}=\dfrac{1}{2}m\times 0^2-\dfrac{1}{2}m\times 0^2$

$W_{gravity}+W_{fric}=0$

W(fric)= - m g h

W(fric) = - 80 x 10 x 15 ( g=10 m/s²)

W(fric) = -12000 J

negative sign indicates that force and displacement is in opposite direction.

5 0

3 years ago

A small grinding wheel has a moment of inertia of 4.0*10-5kgm2. What net torque must be applied to the wheel for its angular acc

kvv77 [185]

Hi there!

We can use the rotational equivalent of Newton's Second Law:

$\huge\boxed{\Sigma \tau = I \alpha}$

Στ = Net Torque (Nm)

I = Moment of inertia (kgm²)

α = Angular acceleration (rad/sec²)

We can plug in the given values to solve.

$\Sigma \tau = (4 * 10^{-5})(150) = \boxed{0.006 Nm}$

4 0

3 years ago

A scientist compares two samples of white powder. One powder was present at the beginning of an experiment. The other powder was

Jet001 [13]

Density of powder 1 = 0.5 g / 45 cm^3 = 1/90 g/cm^3
Density of powder 2 = 1.3 g / 65 cm^3 = 1/50 g/cm^3

Therefore the densities of the two powders are different, hence chemical reaction has occurred.

(note: none of the other choices make sense. In fact, a different density does not necessarily indicate a chemical change, see paragraph below).

Density of powders are not definitive unless they are each of the same size and texture. For example, granular sugar, rock sugar, and icing sugar all have different densities. I would conclude that this experiment does not lend to a reliable answer.

4 0

3 years ago

At t = 0, one toy car is set rolling on a straight track with initial position 13.5 cm, initial velocity -4.2 cm/s, and constant

Blizzard [7]

(a) We must first look at the formulas of the velocities of each toy car. v1 =
-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then
v1 = v2
-4.2 + 2.60t = 5.20
2.60t = 9.40
t = 3.62 s

(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s

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3 0

3 years ago