Answer:
The average force the golf club exerts on the ball is 600 N
Explanation:
Newton's second law of motion states that force, F, is directly proportional to the rate of change of momentum produced
F = m× (v₂ - v₁)/(Δt)
The given parameters of the motion of the ball are;
The mass of the ball, m = 45 g = 0.045 kg
The initial velocity of the ball, v₁ = 0 m/s
The speed with which the ball was hit by the golfer, v₂ = 40 m/s
The duration of contact between the golf club and the ball, Δt = 3 ms = 0.003 seconds (s)
By Newton's law of motion, the average force, 'F', which the golf club exerts on the ball is therefore, given as follows;
F = 0.045 kg × (40 m/s - 0 m/s)/(0.003 s) = 600 N
The average force the golf club exerts on the ball = F = 600 N.
This is an experiment that explains the Bernoulli principle. According to this principle, at the bottom of the spoon, there will be a reduction in pressure.
<h3>Explanation of the Bernoulli principle</h3>
So the pressure at the bottom of the spoon reduces because the velocity of the water is larger and the height of the column of water is smaller at this part.
So the spoon is attracted to the water at the point of lowest pressure because objects gravitate to low-pressure points.
Learn more about the Bernoulli Principle at:
brainly.com/question/24623919
Time= s/v
Speed =5km/h
Time=30min
Distance is required
Distance=time*speed
30min*5km/h=600m
Answer: vacuum
Explanation: The vacuum is the medium from where the sound wave cannot pass. A vacuum is basically an area without any air. Since the sound wave is a mechanical wave that's why it cannot travel through a medium where there is no matter of vibrations to works in, i.e, it can't travel through a vacuum.
The electric force between the two particles are calculated through the equation,
F = kQ₁Q₂ / d²
where F is the force, k is a constant called Coulomb's law constant, Q₁ and Q₂ are the charges, and d is the distance. This equation is called the Coulomb's law.
It can be seen from the equation above that the electric forces between the objects are majorly affected by the substance's charges and distance.
The answer to this item is therefore letter A.