Answer:
Explanation:
Initial volume v₁ =46 x 10⁻⁶ m³
Initial temperature T₁ = 438.28 + 273 = 711.28 K
Initial pressure P₁ = nRT₁ / v₁
= 30.4 x8.3 x 711.28 / (46 x 10⁻⁶ )
= 3901.5 x 10⁶ Pa
Final temperature T₂ = 824 + 273 = 1097 K
Final volume V₂ =?
For isobaric process
v₁ / T₁ = V₂ / T₂
V₂ = V₁ X T₂ /T₁
= 46 X 10⁻⁶ X 1097/ 711.28
= 70.94 X 10⁻⁶ m³ = 70.94 cm³
b ) For isothermal change
P₁ V₁ = P₂V₂
P₂ = P₁V₁ / V₂
= 3901.5 X 10⁶ X 46 / 24.3
7385.55 X 10⁶ Pa.
Do not see the statements
I think the correct answer from the choices listed above is the second option. The thermosphere has less air pressure than the mesosphere <span>because the farther away you are from the surface of the earth the lesser amount of gases present.</span>
