Explanation:
Mass of fructose = 33.56 g
Mass of water = 18.88 g
Total mass of the solution = Mass of fructose + Mass of water = M
M = 33.56 g + 18.88 g =52.44 g
Volume of the solution = V = 40.00 mL
Density =
a) Density of the solution:

b) Molar mass of fructose = 180.16 g/mol
Moles of fructose = 
Molar mass of water = 18.02 g/mol
Moles of water= 
Mole fraction of fructose in this solution:


Mole fraction of water = 
c) Average molar mass of of the solution:
=

d) Mass of 1 mole of solution = 42.50 g/mol
Density of the solution = 1.311 g/mL
d) Specific molar volume of the solution:


Answer:
I can't say that it is definitely write.
HHH
H-C-C-C
Yeah what is the question
Pressure of the gas inside the container is 662.59 torr.
<h3>What is ideal gas law?</h3>
The ideal gas law (PV = nRT) connects the macroscopic characteristics of ideal gases. An ideal gas is one in which the particles are both non-repellent and non-attractive to one another (have no volume).
The general law of ideal gas can be applied here: PV is equal to nRT, where P is the gas pressure in atm.
V is the number of moles of the gas in a mole, and n is the volume of the gas in L. R is the universal gas constant. T is the temperature(Kelvin) of the gas.
If P and T are different values and n and V are constants, then
(P₁T₂) = (P₂T₁).
P₁ = 735 torr, T₁ = 29°C + 273 = 302 K,
P₂ = ??? torr, T₂ = 62°C + 273 = 335 K.
∴ P₂ = (P₁T₂)/(P₁) = (735 torr)(302 K)/(335 K) = 662.59 torr.
To know more about ideal gas law visit:
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