Answer:
Electrons accelerated to high velocities travel in straight lines through an empty cathode ray tube and strike the glass wall of the tube, causing excited atoms to fluoresce or glow.
Answer:
2.726472 s more or 1.5874 times more time is taken than 10-lb roast.
Explanation:
Given:
- The cooking time t is related the mass of food m by:
t = m^(2/3)
- Mass of roast 1 m_1 = 20 lb
- Mass of roast 2 m_2 = 10 lb
Find:
how much longer does a 20-lb roast take than a 10-lb roast?
Solution:
- Compute the times for individual roasts using the given relation:
t_1 = (20)^(2/3) = 7.36806 s
t_2 = (10)^(2/3) = 4.641588 s
- Now take a ration of t_1 to t_2, to see how many times more time is taken by massive roast:
t_1 / t_2 = (20 / 10)^(2/3)
- Compute: t_1 / t_2 = 2^(2/3) = 1.5874 s
- Hence, a 20-lb roast takes 1.5874 times more seconds than 10- lb roast.
t_2 - t_1 = 2.726472 s more
Answer: h = u^2 / 2g
Explanation:
Given the following :
Horizontal Velocity of projection= u
If :
magnitude of horizontal = magnitude of vertical Displacement
u = u
Minimum height of tower (h) =?
Horizontal Velocity = u
Gravity potential energy = mgh - - - (1)
Kinetic energy = 1/2 mu^2 - - - (2)
m = mass
Where u = magnitude of velocity
g = acceleration due to gravity
h = height
Equating (1) and (2)
mgh = 1/2 mu^2
gh = 1/2 mu^2
2gh = u^2
u = √2gh
Vertical component of Velocity 'v' will be:
u = √2gh
u = √2 × g × h
Square both sides
u^2 = 2 × g × h
h = u^2 / 2g