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MariettaO [177]
3 years ago
10

How much current is in a circuit that includes a 9.0-volt battery and a bulb with a resistance of 4.0 ohms? A. 0.44 amps B. 36 a

mps C. 2.3 amps D. 13 amps
Physics
1 answer:
bija089 [108]3 years ago
8 0

Answer:

C. 2.3A

Explanation:

V/Ω=A

9V / 4Ω = 2.25 ≅ 2.3A

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(answer the question or get reported) Please solve it with the steps thanks :)​
DaniilM [7]

Answer:

Fx = 35.36 N

Fy = 35.36 N

Explanation:

From the question,

The X component of the force is

Fx = Fcos∅.................. Equation 1

Where Fx = X component of the force, F = Force, ∅ = Angle to the horizontal.

Give: F = 50 N, ∅ = 45°

Substitute into equation 1

Fx = 50(cos45°)

Fx = 50(0.7071)

Fx = 35.36 N

Similarly,

For Y component

Fy = Fsin∅

Where F y = Y component

Fy = 50(sin45°)

Fy = 50(0.7071)

Fy = 35.36 N

4 0
2 years ago
Help awnser need experts​
pishuonlain [190]

12. The answer would be C. 1.50 s. This is because if you divide 60 by 40, you will get 1.5.

13. For this one I'm not sure, but what I can tell you is that the heavier something is the faster it will sink, the lighter it is, it will float.

5 0
3 years ago
If earth's mass were half its actual value but its radius stayed the same, the escape velocity of earth would be:________
siniylev [52]

If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

<h3>What is an escape velocity?</h3>

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

V_e=\sqrt{\dfrac{2GM}{r}}

Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

V_e=\sqrt{\dfrac{2GM}{r\times 2}}

V_e = \sqrt{\dfrac{GM}{r}}.

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

To know more about escape velocity follow

brainly.com/question/14042253

#SPJ4

8 0
1 year ago
When you ask you friend for hoemwork answers and he answers like a year later hahahah
Hitman42 [59]
G that’s a nice friend
5 0
3 years ago
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What physical quantity is a measure of the amount of inertia an object has?
satela [25.4K]
Mass is the physical quantity
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3 years ago
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