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iogann1982 [59]
3 years ago
7

A dog pushes a toy horizontally on a frictionless floor with a net force of 2.0\, \text N2.0N for 1.0\,\text m1.0m. How much kin

etic energy does the toy gain?
Physics
2 answers:
TiliK225 [7]3 years ago
6 0

Answer: 2 J

Explanation: Kinetic energy is possessed by a body due to virtue of its motion. A body gains kinetic energy when some work is done on it.

W = Δ K.E.

We know that work is said to be done on a body when a force causes displacement of the body.

W = F.s

It is given that net force on the toy, F = 2.0 N which displaces the toy by, s = 1.0 m.

Hence, work done on the toy, W = 2.0 N × 1.0 m = 2 J which is equal to the kinetic energy gained by the toy.  

IRINA_888 [86]3 years ago
4 0

Answer:

2.0 J

Explanation:

Since the surface is frictionless, we can solve the problem by using the work-energy theorem, which states that the work done on the toy is equal to the kinetic energy gained by the toy:

W=\Delta E_k

where

W is the work done on the toy

\Delta E_k is the kinetic energy gained by the toy

The work done can be calculated as the product between the force applied on the toy and its displacement, so:

W=Fd=(2.0 N)(1.0 m)=2.0 J

Therefore, according to the work-energy theorem, the toy has gained 2.0 J of kinetic energy.

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Artyom0805 [142]

Answer:

f=81.96 \ Hz

Explanation:

Givens

L=95cm

m_{sculpture} =13kg

m_{wire}=5g

The frequency is defined by

f=\frac{v}{\lambda}

Where v is the speed of the wave in the string and \lambda is its wave length.

The wave length is defined as \lambda = 2L = 2(0.95m)=1.9m

Now, to find the speed, we need the tension of the wire and its linear mass density

v=\sqrt{\frac{T}{\mu} }

Where \mu=\frac{0.005kg}{0.95m}= 5.26 \times 10^{-3} and the tension is defined as T=m_{sculpture} g=13kg(9.81 m/s^{2} )=127.53N

Replacing this value, the speed is

v=\sqrt{\frac{127.53N}{5.26 \times 10^{-3} } }=155.71 m/s

Then, we replace the speed and the wave length in the first equation

f=\frac{v}{\lambda}\\f=\frac{155.71 m/s}{1.9m}\\ f=81.96Hz

Therefore, the frequency is f=81.96 \ Hz

3 0
3 years ago
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Without using a micrometer screw gauge, how do I find the average diameter of a long piece of thin wire using a metre rule and a
Mice21 [21]

Answer:

Wind the long piece of thin wire around the uniform glass rod multiple times, find the length of the total diameters using the metre ruler, and divide by the number of times you wound it around the rod.

Explanation:

Since the diameter of one long piece of thin wire is too thin to be measured by a metre ruler, you can wind it multiple times and push it side by side to get a length you can measure.

For example, if you wound it around 20 times and the total length of 20 diameters of the wire side-by-side is 2.0 cm, one winding, which is the diameter would be 2.0cm ÷ 20 = 0.10cm or 1mm.

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Answer:

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serious [3.7K]

Answer:

The answer is 4N or B

Explanation:

Just the equation W = F x D.

We have W = 8 J and D = 2 m using algebra ....

8J/2m = F ... F = 4.

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3 years ago
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What's is meant by relative motion?​
saveliy_v [14]

Relative motion means a motion relative to a reference point. We can also say, relative motion means motion referred or observed from a reference point.

For example, Alex is in a train and Ace is at the station, when the train starts moving, for Ace it is moving at a speed of 10 m/s, but for Alex it is moving at 0 m/s, or we can say that it is at rest for Alex, but in motion for Ace. This is relative motion.

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