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qwelly [4]
2 years ago
13

Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smalle

r sphere. If the electric field just outside of the smaller sphere is E0, then the electric field just outside of the larger sphere is
3 Two conducting spheres are each given a charge Q.
1/9 Two conducting spheres are each given a charge Q.
9 Two conducting spheres are each given a charge Q.
1/3 Two conducting spheres are each given a charge Q.
Physics
1 answer:
Vinil7 [7]2 years ago
7 0

Answer:

1/9 of that just outside the smaller sphere

Explanation:

The electric field strength produced by a charged sphere outside the sphere itself is equal to that produced by a single point charge:

E=k\frac{Q}{r^2}

where

k is the Coulomb's constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

Calling R the radius of the first sphere, the electric field just outide the surface of the first sphere is

E_0=k\frac{Q}{R^2}

The second sphere has a radius which is 3 times that of the smaller sphere:

R'=3R

So, the electric field just outside the second sphere is

E'=k\frac{Q}{R'^2}=k\frac{Q}{(3R)^2}=\frac{1}{9}(k\frac{Q}{R^2})=\frac{E_0}{9}

So, the correct answer is 1/9.

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If an object force of 50 N is used to move an object a distance of 20 m, what distance must the object be moved if the input for
steposvetlana [31]

Answer:

\ d_{out} = 100 \ m.

Explanation:

Given data:

F_{in} = 50 \ \rm N

F_{out} = 10 \ \rm N

d_{in} = 20 \ m

Let the distance traveled by the object in the second case be d_{out}.

In the given problem, work done by the forces are same in both the cases.

Thus,

W_{in} = W_{out}

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\Rightarrow \ d_{out} = \frac{F_{in}.d_{in}}{F_{out}}

\ d_{out} = \frac{50 \times 20}{10}

\ d_{out} = 100 \ m.

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2 years ago
A 10 m long clothesline is strung so that it is perfectly horizontal. when a shirt is hung in the exact center the line sags to
Leto [7]

Answer:

x = 0.0873 m

Explanation:

given,

length of clothesline = 10 m

the line sags to create an angle that is 1 degree below the horizontal on each end.

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as the shirt is hang at the center distance will be equal to 5 m.

now

tan \theta = \dfrac{d_e}{d}

tan \theta = \dfrac{x}{5}

tan 1^0 = \dfrac{W}{5}

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A truck travels to and from a stone quarry that is located 2.5km to the east.
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Answer:

Distance is 5.0 km and displacement is 0 km.

Explanation:

The diagram is shown below.

Distance is the total length that the truck covers along the complete journey. The truck moves from a stone quarry covering a length of 2.5 km and then again come back to the same point and thus covering another 2.5 km. Therefore, the total length covered by the truck is the sum of forward and backward paths which is equal to 5.0 km.

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