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qwelly [4]
3 years ago
13

Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smalle

r sphere. If the electric field just outside of the smaller sphere is E0, then the electric field just outside of the larger sphere is
3 Two conducting spheres are each given a charge Q.
1/9 Two conducting spheres are each given a charge Q.
9 Two conducting spheres are each given a charge Q.
1/3 Two conducting spheres are each given a charge Q.
Physics
1 answer:
Vinil7 [7]3 years ago
7 0

Answer:

1/9 of that just outside the smaller sphere

Explanation:

The electric field strength produced by a charged sphere outside the sphere itself is equal to that produced by a single point charge:

E=k\frac{Q}{r^2}

where

k is the Coulomb's constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

Calling R the radius of the first sphere, the electric field just outide the surface of the first sphere is

E_0=k\frac{Q}{R^2}

The second sphere has a radius which is 3 times that of the smaller sphere:

R'=3R

So, the electric field just outside the second sphere is

E'=k\frac{Q}{R'^2}=k\frac{Q}{(3R)^2}=\frac{1}{9}(k\frac{Q}{R^2})=\frac{E_0}{9}

So, the correct answer is 1/9.

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