only reactants are present
If equllibrium constant is greater than 10^3 then product
predominates
If equllibrium constant is greater than 10^ -3 then reactant predominates
in between 10^3 and 10^-3 the reaction is in equllibrium
and we see that the above value is 10^-31, it is very small so the answer is reactants are presents
When a compound containing C, H and O is completely combusted in air what reactant besides the hydrocarbon is involved in the reaction is Oxygen.
<h3>What is hydrocarbon?</h3>
A hydrocarbon is an organic molecule composed completely of hydrogen and carbon in organic chemistry. Group 14 hydrides include hydrocarbons. Hydrocarbons are often colourless and hydrophobic, with scents that are weak or exemplified by gasoline and lighter fluid. They exist in a wide range of molecular forms and phases, including gases (like methane and propane), liquids (like hexane and benzene), low melting solids (like paraffin wax and naphthalene), and polymers (such as polyethylene and polystyrene). Hydrocarbon refers to naturally occurring petroleum, natural gas, and coal, as well as their hydrocarbon derivatives and refined forms, in the fossil fuel industry. The primary source of energy on the planet is the combustion of hydrocarbons.
To learn more about hydrocarbons visit:
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Answer:
300K.
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 300L
Initial temperature (T1) = 200K
Final volume (V2) = 450L
Final temperature (T2) =..?
Since the pressure is constant, the gas is obeying Charles' law.
Using the Charles' law equation, we can obtain the new temperature of the gas as follow:
V1/T1 = V2/T2
300/200 = 450/T2
Cross multiply to express in linear form
300 x T2 = 200 x 450
Divide both side by 300
T2 = (200 x 450)/ 300
T2 = 300K
Therefore, the new temperature of the gas is 300K.
1. To step
2. To throw
3. Measure
4. To join
5. Place
<span>(3) C4H8</span>
C=12, H=1
CH2= 12+2=14
(CH2)n=56g/mol
14n=56
n=4
(CH2)4=C4H8
