PLEASE HELP ITS DUE IN 12 MINUTES

Technician A says that in a series circuit, if one light goes out, the rest of the lights stay on. Technician B says that in a p

vivado [14]

Answer:

Explanation:

Technician A is incorrect as in series circuit the current is the same for all the resistors and if one bulb fails in the path then the circuit is incomplete and therefore no flow of current.

Technician B is correct as in parallel circuit there are multiple paths for current through which it can pass and malfunctioning of one resistor does not affect the other.

6 0

3 years ago

Water at 288.7 k flows through a 15.24-cm. diameter horizontal pipe into a 190-l drum. determine the minimum time it will take t

nikdorinn [45]

The flow will be laminar if Reynold's number $N_{R}$ is less than 2000.

Use the Reynold's formula and rearrange to calculate velocity of water in the pipe.

$N_{R} = \frac{v D}{\nu}$

Where, $v$ is velocity of the fluid, $D$ is the diameter of pipe, and $\nu$ is the kinematic viscosity i.e. $1.12 \times 10^{-6} m^2/s$ for water at 288.7 K from Appendix.

So, velocity is:

$v = \frac{N_{R} \nu}{D}$

The flow rate <em>Q</em>:

$Q = vA=v\pi D^2/4=\frac{\frac{N_R \nu}{D} \pi D^2}{4} =[tex] t = \frac{V}{\frac{N_R \nu \pi D}{4}} = \frac{4V}{N_R \nu \pi D} =\frac{4 \times 190 L\frac{10^{-3} m^3}{L}}{2000 \times 1.12\times 10^{-6} m^2/s \pi 15.24 cm\frac{1 m}{100 cm}} = 2226.3 s \frac{1 min}{60 s}= 37.1 min$ [/tex]

Where A is the area of cross section of pipe.

The time taken to fill is:

$t = Q/V$

Where V is the capacity of the tank.

7 0

3 years ago

A person in a kayak starts paddling, and it accelerates from 0 to 0.65 m/s in a distance of 0.40 m. If the combined mass of the

SCORPION-xisa [38]

Answer:

Magnitude of the net force acting on the kayak = 39.61 N

Explanation:

Considering motion of kayak:-

Initial velocity, u = 0 m/s

Distance , s = 0.40 m

Final velocity, v = 0.65 m/s

We have equation of motion v² = u² + 2as

Substituting

v² = u² + 2as

0.65² = 0² + 2 x a x 0.4

a = 0.53 m/s²

We have force, F = ma

Mass, m = 75 kg

F = ma = 75 x 0.53 = 39.61 N

Magnitude of the net force acting on the kayak = 39.61 N

6 0

3 years ago

a metal bar 70cm long and 4.00 kg in mass supported on two knief -edge placed 10 cm from each end. a 6.00 kg weight is suspended

Klio2033 [76]

First, you make a diagram of all the forces acting on the system. This is shown in the figure. We have to determine F1 and F4. Let's do a momentum balance. Momentum is conserved so the summation of all momentum is equal to zero. Momentum is force*distance.

To determine F1: (reference is F4, so F4=0)

∑Momentum = 0 = -F2 - F3 + F1
0 = (-4 kg)(9.81 m/s2)(0.25m)-(6kg)(9.81 m/s2)(0.5-0.3m)+F1(0.5-0.1m)
F1 = 53.96 N (left knife-edge)

To determine F4: (reference is F1, so F1=0)

∑Momentum = 0 = -F2 - F3 + F4
0 = (-4 kg)(9.81 m/s2)(0.25m)-(6kg)(9.81 m/s2)(0.5-0.2m)+F4(0.5-0.1m)
F4 = 68.67 N (right knife-edge)

4 0

3 years ago

Read 2 more answers

how do i write this to where it is true? in the blue is a statement and the attached piece is false so i have to make it true an

OlgaM077 [116]

Answer:

cross out the false piece in blue and write the true piece in red

4 0

3 years ago