Answer:
4.7 s
Explanation:
The complete question is presented in the attached image to this solution.
v(t) = 61 - 61e⁻⁰•²⁶ᵗ
At what time will v(t) = 43 m/s?
We just substitute 43 m/s into the equation for the velocity of the diver and solve for t.
43 = 61 - 61e⁻⁰•²⁶ᵗ
- 61e⁻⁰•²⁶ᵗ = 43 - 61 = -18
e⁻⁰•²⁶ᵗ = (18/61) = 0.2951
In e⁻⁰•²⁶ᵗ = In 0.2951 = -1.2205
-0.26t = -1.2205
t = (1.2205/0.26) = 4.694 s = 4.7 s to the nearest tenth.
Hope this Helps!!!
Answer:
a cornea that is not curved enough
Yes, that's right. It's the 'Planck' length, not the 'Planet' length.
You could easily find these with a web search. But in gratitude
for the bountiful 5 points, I've saved you the trouble.
AND guess what ! By doing that, I learned something, and
you didn't.
Speed of light (c): 299,792,458 meters per second
Gravitational constant (G): 6.67 x 10⁻¹¹ newton-meter²/kilogram²
Planck's Konstant (h): 6.63 x 10⁻³⁴ joule-second
Planck Length: 1.6 x 10⁻³⁵ meter
(about 10⁻²⁰ the size of a proton)
Planck Time: 10⁻⁴³ second
(about the time it takes to travel
a Planck Length at the speed of light)
