B was very surprised by the music
Answer:
(a) The work done is 0.05 J
(b) The force will stretch the spring by 3.8 cm
Explanation:
Given;
work done in stretching the spring from 30 cm to 45 cm, W = 3 J
extension of the spring, x = 45 cm - 30 cm = 15 cm = 0.15 m
The work done is given by;
W = ¹/₂kx²
where;
k is the force constant of the spring
k = 2W / x²
k = (2 x 3) / (0.15)²
k = 266.67 N/m
(a) the extension of the spring, x = 37 cm - 35 cm = 2 cm = 0.02 m
work done is given by;
W = ¹/₂kx²
W = ¹/₂ (266.67)(0.02)²
W = 0.05 J
(b) force = 10 N
natural length L = 30 cm
F = kx
x = F / k
x = 10 / 266.67
x = 0.0375 m
x = 3.75 cm = 3.8 cm
Thus a force of 10 N will stretch the spring by 3.8 cm
Answer:
Part b)
h = 78.5 m
Part c)
v = 39.24 m/s
Explanation:
Part b)
If ball need t = 0 to t = 4 s then height of the tower is the total displacement of the ball in t = 4 s interval
here if ball start from rest
then its displacement is given as
Part c)
Speed of the bearing at the end of the motion of the ball
Answer:
Joint application development
Explanation:
Joint application development is a computer based system used for development process. It interface between the users and designer of the system in development.
Two things are said to be in contact if the smallest distance between a point in one of them and a point in the other one is zero.
