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Andre45 [30]
2 years ago
14

Sphere is fired downwards into a medium with an initial speed of 27 m/s. If it experiences a

Physics
1 answer:
anygoal [31]2 years ago
8 0

Answer:

33 m/s

first i do 27+6=33 +s2=

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g a stone with mass m=1.60 kg IS thrown vertically upward into the air with an initial kinetic energy of 470 J. the drag force a
otez555 [7]

Answer:

Height reached will be 28.35 m

Explanation:

Here we can use the work energy theorem to find the maximum height

As we know by work energy theorem

Work done by gravity + work done by friction = change in kinetic energy

-mgh - F_f h = 0 - \frac{1}{2}mv_i^2

now we will have

-1.60(9.8)(h) - 0.900(h) = - 470

-16.58 h = -470

h = 28.35 m

so here the height raised by the stone will be 28.35 m from the ground after projection in upward direction

5 0
3 years ago
Continental crust is primarily witch kind of rock
kotegsom [21]
The correct answer is granite oceanic. Continental crust is primarily a granite oceanic. Continental crust is the layers of sedimentary, igneous, and metamorphic rocks that form the area of the shallow seabed that is near the shore. 
7 0
3 years ago
The law of conservation of momentum states that...
Brums [2.3K]

Answer:

The momentum before is equal to the momentum after

Explanation:

It is equal and should level out in an equation.

4 0
3 years ago
The heat pump is designed to move heat. This is only possible if certain relationships between the heats and temperatures at the
Pie

Answer:

There are no answer chooses to this question

Explanation:

7 0
3 years ago
a water bomber flying with a horizontal speed of 85m/s at a height of 3000m drops a load on a fire below. How far in front of th
Andreyy89

Answer:

2081.65 m

Explanation:

We'll begin by calculating the time taken for the load to get to the target. This can be obtained as follow:

Height (h) = 3000 m

Acceleration due to gravity (g) = 10 m/s²

Time (t) =?

h = ½gt²

3000 = ½ × 10 × t²

3000 = 5 × t²

Divide both side by 5

t² = 3000 / 5

t² = 600

Take the square root of both side

t = √600

t = 24.49 s

Finally, we shall determine the distance from the target at which the load should be released. This can be obtained as follow:

Horizontal velocity (u) = 85 m/s

Time (t) = 24.49 s

Horizontal distance (s) =?

s = ut

s = 85 × 24.49

s = 2081.65 m

Thus, the load should be released from 2081.65 m.

3 0
3 years ago
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