A motor lifts a 500kg elevator a height of 100 m at a constant speed in 50 secs. How much power did the motor supply
1 answer:
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Answer:
Lifting force, F = 21240 N
Explanation:
It is given that,
Mass of the helicopter, m = 1800 kg
It rises with an upward acceleration of 2 m/s². We need to find the lifting force supplied by its rotating blades. It is given by :
F = mg + ma
Where
mg is its weight
and "ma" is an additional acceleration when it is moving upwards.
So,
F = 21240 N
So, the lifting force supplied by its rotating blades is 21240 N. Hence, this is the required solution.