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Yakvenalex [24]
3 years ago
9

Mixture E consists of two esters X with two functions, Y with three functions in open circuit (MX < My). Complete combustion

of mg of E yields 0.3 mol CO2 and 0.24 mol H2O. On the other hand, complete hydrolysis of milligram E with NaOH solution yields 3.48 grams of a mixture of two alcohols and a salt mixture of two carboxylic acids. Burning all two alcohols requires 0.1575mol 0 , yielding 0.12 mol CO2 . Find the percent by mass of Y in E.​
Chemistry
1 answer:
Taya2010 [7]3 years ago
7 0

Answer:

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The process that makes atmospheric nitrogen available to plants by mutualistic and free-living bacteria is called
artcher [175]
Nitrogen fixation is the process that makes atmospheric nitrogen available to plants by mutualistic and free-living bacteria. The process is undertaken by the rhizobium bacteria that live in root roots of plants such as legumes. The mutualistic relationship is that the plant supplies the bacteria with a habitat in which to live, water, and nutrients, and the bacteria supply nitrogen for making plant proteins. 
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4 years ago
5. By approximately what factor would the mass of a sample of copper-66
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That’s picture right there should help u with your works

7 0
3 years ago
Read 2 more answers
a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter
ladessa [460]

Answer:

The concentration of chloride ion is 2.82\times10^{-3}\;mol/L

Explanation:

We know that 1 ppm is equal to 1 mg/L.

So, the Cl^- content 100 ppm suggests the presence of 100 mg of Cl^- in 1 L of solution.

The molar mass of Cl^- is equal to the molar mass of Cl atom as the mass of the excess electron in Cl^- is negligible as compared to the mass of Cl atom.

So, the molar mass of Cl^- is 35.453 g/mol.

Number of moles = (Mass)/(Molar mass)

Hence, the number of moles (N) of Cl^- present in 100 mg (0.100 g) of Cl^- is calculated as shown below:

N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol

So, there is 2.82\times10^{-3}\;mol of Cl^- present in 1 L of solution.

5 0
4 years ago
the reaction AB2C (g) &lt;---&gt; B2 (g) + AC (g) reached equilibrium at 900 K in a 5.00 L vessel. At equilibrium 0.0840 mol of
Verizon [17]

Answer:

k = 4,92x10⁻³

Explanation:

For the reaction:

AB₂C (g) ⇄ B₂(g) + AC(g)

The equilibrium constant, k is defined as:

k = \frac{[B_{2}][AC]}{[AB_2C]} <em>(1)</em>

Molar concentration of the species are:

[AB₂C]: 0,0840mol / 5L = <em>0,0168M</em>

[B₂]: 0,0350mol / 5L = <em>0,0070M</em>

[AC]: 0,0590mol / 5L = <em>0,0118M</em>

Replacing this values in (1):

k = \frac{[0,0070][0,0118]}{[0,0168]}

<em>k = 4,92x10⁻³</em>

I hope it helps!

7 0
3 years ago
In the equation C3H8 + O2 -&gt; CO2 + H2O, what coefficient belongs in front of the O2 group?
tankabanditka [31]

Answer:

3

Explanation:

C3H8. + 5O2. ::: 3CO2. + 4H2O

4 0
3 years ago
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