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2 years ago

What are the 4 properties of hydrogen bonds?

Chemistry

1 answer:

tiny-mole [99]2 years ago

7 0

Answer:

Solubility, Volatility, Viscosity and Surface Tension.

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Which of the following changes to a system WILL NOT result in an increase in the system’s pressure?

Sophie [7]

Answer:

B. All the rest raise P.

Explanation:

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2 years ago

What are some uses for graphite

erma4kov [3.2K]

Because it is a solid material, it is known as a dry lubricant. This is useful inapplications where “wet” lubricants, such as oil, cannot be used. Graphite is the only non-metal element that is a good conductor of electricity. Natural graphite is used mostly in what are called refractory applications

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3 years ago

In your own words, describe how the energy of a pendulum is changed as it moves through one cycle of its motion. Pls help online

ruslelena [56]

In a perfect world without air resistance, the top of the swing would have the most potential energy, but the least amount of kinetic energy. As the pendulum falls down, it gains more kinetic energy as it travels faster due to gravitational acceleration but loses more potential energy as it loses height. The total amount of energy in the system (the sum of kinetic and potential energy) stays the same.

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3 years ago

An aqueous solution of blue copper(II) ions can react with chloride ions to form a yellow copper compound. The ionic equation fo

klio [65]

Since the forward reaction is endothermic (heat is consumed in the reaction) that means that the enthalpy change for the forward reaction is a positive value.
Therefore, i would say that the reverse or backward reaction is exothermic (heat is released in the reaction to the sorroundings) and that the enthalpy change is a negative value.

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3 years ago

A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h

Ksenya-84 [330]

Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution : 0.0328 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0328=\frac{\text{Number of moles}}{0.250 L}$

Moles of HCl in 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution : 0.0245 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}$

Moles of NaOH in 0.100 L solution = 0.00245 moles

3) Concentration of hydrochloric acid in the resulting solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.

Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L

Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles = 0.00575 moles

$Molarity=\frac{\text{number of moles}}{\text{volume of solution in L}}$

Molarity of HCl left un-neutralized : $\frac{0.00575 moles}{0.350L}=0.0164 M$

0.0164 molar concentration of hydrochloric acid in the resulting solution.

3 0

3 years ago