As you move down through the family of alkali metals, the first ionization energy ________ because
2 answers:
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The mentioned molecule with formula, CH₃NO where no bond is found between N and O can be depicted as formamide is shown in the attachment below.
The formal charges = Number of valence electrons for the atom (V) - the number of electrons in lone pairs (N) - 1/2 (number of electrons in bond pairs, B)
FC = V - N - B/2
Thus, there is a need to calculate valence electrons, electrons in lone pairs, and the number of electrons in bond pairs for each atom in the mentioned molecule.
V or valence electrons on C = 4e, on H = 1e, on N = 5e, and on O = 6e.
N or electrons in lone pairs on C = 0e, on H = 0e, on N = 2e, and on O = 4e.
B or number of electrons in bond pairs for C = 8e, for H = 2e, for N = 6e, and for O = 4e.
Thus, the formal charges for each will be,
C = 4 - 0 - (8/2) = 0
H = 1 - 0 - (2/2) = 0
N = 5 - 2 - (6/2) = 0
O = 6 - 4 - (4/2) = 0
Lewis dot structure for the given molecule is given in the attachment below:
Answer:
ZnS
Explanation:
1. Number of Zn atoms
4 internal atoms = 4 Zn atoms
2. Number of S atoms
8 corners × ⅛ S atom/corner + 6 faces × ½ S atom/face = 1 S atom + 3 S atoms = 4 S atoms
3. Empirical formula
The atomic ratio is
4Zn:4S = 1Zn:1S
The empirical formula is ZnS.
